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Vedmedyk [2.9K]
3 years ago
13

Find the unit rate 34 carbs for every 1/3 serving

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

102.010201 carb per serving

Step-by-step explanation:

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Divide 7/15 by 3/5. <br> A. 75/21<br> B. 7/9<br> C. 7/25<br> D. 21/75
Digiron [165]
In this question there is nothing complicated. Only thing is to know the way fractions can be divided. Once that is known the problem would be one of the easiest to solve. Now let us get back to the problem and look at all the information's that are given in the question.
Divide 7/15 by 3/5 = (7/15)/(3/5)
                              = (7 * 5)/(15 * 3)
                               = (35/45)
Dividing the numerator and the denominator by 5 for simplifying purpose, we get
                               = 7/9
So from the above deduction we can easily conclude that 7/9 is the correct answer and option "B" is the correct option among all the options given in the question.
5 0
3 years ago
Read 2 more answers
Which expression can be used to find the surface area of the following rectangular prism?
PolarNik [594]

Answer:

C.

Step-by-step explanation:

3 times 2 is 6, 2 times 5 is 10, 5 times 3 is 15. However you need 2 for each since there are 3 sets of two equal faces. So it will be 6+6+10+10+15+15

4 0
3 years ago
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A highway map of Ohio has a coordinate grid superimposed on top of the state. Springfield is at point (1, –4) and Columbus is at
Vedmedyk [2.9K]
The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.

Rest Area=((1+7)/2, (-4+1)/2)

Rest Area=(4, -1.5)

The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.

d^2=(x2-x1)^2+(y2-y1)

d^2=(7-1)^2+(1--4)^2

d^2=36+25

d^2=61

d=√61  and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:

D=5.38√61 mi

D≈42.02mi  (to nearest hundredth of a mile)
3 0
3 years ago
How do i solve 4m^2+3m-1=0 using the quadratic formula
elixir [45]
Quadratic formulat is used when a^2+bx+c=0 x= \frac{-b+/- \sqrt{b^{2}-4ac}   }{2a} 4m^2+3m-1=0 a=4 b=3 c=-1 input x= \frac{-3+/- \sqrt{3^{2}-4(4)(-1)}   }{2(4)} x= \frac{-3+/- \sqrt{9+16}   }{8} x= \frac{-3+/- \sqrt{25}   }{8} x= \frac{-3+/-5  }{8} x= \frac{-8}{8} or \frac{2}{8} x=-1 or 1/4
8 0
3 years ago
What is the Smallest numbers : <br> p = x^2 + 2x +2 / x+1 (x&gt;-1) <br> t= 1/x + 4/1-x (0
OverLord2011 [107]

Answer:

I exactly don't know the answer

5 0
2 years ago
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