Ask question

Ask question

All categories

3 years ago

15

Ralph has a balance of $1350 on his credit card, which he plans to pay off by making a payment of the same amount each month. Wh

ich of these monthly amounts will allow Ralph to pay off his balance the fastest? A. $35. B. $30. C. $40. D. $25

1 answer:

Mamont248 [21]3 years ago

7 0

Answer:

The answer is 40$ because 40$ makes the most sense in this particular equation

Step-by-step explanation:

You might be interested in

Which equation is y= 2x ^2 - 8x +9 rewritten in vertex form.

tankabanditka [31]

<span>y= 2x ^2 - 8x +9

</span>y = a(x - h)2 + k, where (h, k) is the vertex<span> of the parabola
</span>so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------<span>vertex form</span>

7 0

3 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

Read 2 more answers

Is 85/95 greater than 64/76

madam [21]

85/95 is equal to 0.8947
64/76 is equal to 0.842
Therefore, 85/95 is greater

5 0

3 years ago

Please assist me with the domain and range of graphs

Sphinxa [80]

Answer: see below

<u>Step-by-step explanation:</u>

Domain represents the x-values from the smallest (furthest left) to the biggest (furthest right).

Range represents the y-values from the lowest (furthest down) to the highest (furthest up).

Interval notation: If a value is included <em>(closed dot)</em>, use a bracket [ ]

If a value is NOT included <em>(open dot)</em>, use a parenthesis ( )

Note that ± ∞ is never included.

1. Domain: smallest x-value is -4 (included). biggest x-value is 3 (included)

Range: lowest y-value is 2 (included). highest y-value is 5 (included)

D: x = [-4, 3] R: y = [2, 5]

2. Domain: smallest x-value is -∞ (←). biggest x-value is 2 (included)

Range: lowest y-value is 2 (included). highest y-value is ∞ (↑)

D: x = (-∞, 2] R: y = [2, ∞)

3. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is -∞ (↓). highest y-value is ∞ (↑)

D: x = (-∞, ∞) R: y = (-∞, ∞)

4. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is -∞ (↓). highest y-value is 4 (included)

D: x = (-∞, ∞) R: y = (-∞, 4]

5. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is 3 (included). highest y-value is ∞ (↑)

D: x = (-∞, ∞) R: y = [3, ∞)

6. Domain: smallest x-value is -2 (included). biggest x-value is ∞ (→)

Range: lowest y-value is -3 (included). highest y-value is ∞ (↑)

D: x = [-2, ∞) R: y = [-3, ∞)

4 0

3 years ago

Red roses come 3 to a package, and white roses come 5 to a package. If an equal number of red and white roses are wanted to make

Katen [24]

Answer:

B :- 15

Step-by-step explanation:

Given:

A package of red rose contains = 3 pieces

A package of white rose contains = 5 pieces

If an equal number of red and white roses are wanted to make bouquets, what is the minimum number of each that can be purchased ?

Solution:

As here given that there are two types of package of roses, red roses come 3 pieces to each packet and white roses come 5 pieces to each packet and we have to find equal minimum number of red roses as well as white roses to be purchased, we will simply find the Lowest common multiple of 3 and 5.

Multiples of 3 :- 3, 6, 9,12, 15, 18, 21, 24

Multiples of 5 :- 5, 10, 15, 20, 25

<em>Lowest common multiple is 15, that means </em><em>15 is the minimum number of pieces of each that can be purchased to make bouquets.</em>

And number of packets of red rose have to purchase = 3 $\times$ <em><u>5</u></em> = 15, 5 packages.

And number of packets of white rose have to purchase = 5 $\times$ <em><u>3</u></em> = 15 , 3 packages.

4 0

3 years ago

Read 2 more answers