Answer:
Rational Number
Step-by-step explanation:
61 is a rational number because it can be expressed as the quotient of two integers: 61÷ 1
Hope this helps
Answer:
12 and 4 months i think
Step-by-step explanation:
The height of the chimney above the floor of the observation deck is 52.4 ft
Two right angle triangle will be formed.
<h3>Right angle triangle:</h3>
Right angle triangle are triangle that has one of its angle as 90 degrees.
Therefore, using trigonometric ratio,
adjacent side = distance of observer from the bottom edge of the Delaware River drawbridge observation deck
Therefore,
tan 40 = opposite / adjacent
Where
x = height of the observer to the top of the observation deck
tan 40 = x / 200
x = 200 tan 40
x = 167.819926235
x = 167.82 ft
tan 30 = opposite / adjacent
y = height of the observer to the bottom of the observation deck
tan 30 = y / 200
y = 200 tan 30
y = 115.470053838
y = 115.47 ft
The height of the chimney above the floor of the observation deck = height of the observer to the top of the observation deck - height of the observer to the bottom of the observation deck
The height of the chimney above the floor of the observation deck = 167.82 - 115.47 = 52.35 ft
learn more on trigonometric ratio here: brainly.com/question/23854119
Answer:
(30, 90) is a viable solution
(50, 160) is a nonviable solution
Step-by-step explanation:
Answer:
Nico, Raj and Sandra are correct
Step-by-step explanation:
we have
![\frac{2}{5}(5+x)=8](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%285%2Bx%29%3D8)
<em>Method 1</em>
Solve for x
That means ----> isolate the variable x
we have
![\frac{2}{5}(5+x)=8](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%285%2Bx%29%3D8)
Multiply by 5/2 both sides
![(\frac{5}{2})\frac{2}{5}(5+x)=(\frac{5}{2})8](https://tex.z-dn.net/?f=%28%5Cfrac%7B5%7D%7B2%7D%29%5Cfrac%7B2%7D%7B5%7D%285%2Bx%29%3D%28%5Cfrac%7B5%7D%7B2%7D%298)
![5+x=20](https://tex.z-dn.net/?f=5%2Bx%3D20)
subtract 6 both sides
![5+x-5=20-5](https://tex.z-dn.net/?f=5%2Bx-5%3D20-5)
![x=15](https://tex.z-dn.net/?f=x%3D15)
<em>Method 2</em>
Solve for x
That means ----> isolate the variable x
we have
![\frac{2}{5}(5+x)=8](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%285%2Bx%29%3D8)
Multiply by 1/2 both sides
![(\frac{1}{2})\frac{2}{5}(5+x)=(\frac{1}{2})8](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%29%5Cfrac%7B2%7D%7B5%7D%285%2Bx%29%3D%28%5Cfrac%7B1%7D%7B2%7D%298)
![\frac{1}{5}(5+x)=4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%285%2Bx%29%3D4)
Multiply by 5 both sides
![(5)\frac{1}{5}(5+x)=(5)4](https://tex.z-dn.net/?f=%285%29%5Cfrac%7B1%7D%7B5%7D%285%2Bx%29%3D%285%294)
![5+x=20](https://tex.z-dn.net/?f=5%2Bx%3D20)
subtract 6 both sides
![5+x-5=20-5](https://tex.z-dn.net/?f=5%2Bx-5%3D20-5)
![x=15](https://tex.z-dn.net/?f=x%3D15)
<em>Method 3</em>
Solve for x
That means ----> isolate the variable x
we have
![\frac{2}{5}(5+x)=8](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%285%2Bx%29%3D8)
Apply distributive property left side
![\frac{2}{5}(5)+\frac{2}{5}(x)=8](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%285%29%2B%5Cfrac%7B2%7D%7B5%7D%28x%29%3D8)
![2+\frac{2}{5}(x)=8](https://tex.z-dn.net/?f=2%2B%5Cfrac%7B2%7D%7B5%7D%28x%29%3D8)
subtract 2 both sides
![2+\frac{2}{5}(x)-2=8-2](https://tex.z-dn.net/?f=2%2B%5Cfrac%7B2%7D%7B5%7D%28x%29-2%3D8-2)
![\frac{2}{5}(x)=6](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28x%29%3D6)
Multiply by 5/2 both sides
![(\frac{5}{2})\frac{2}{5}(x)=(\frac{5}{2})6](https://tex.z-dn.net/?f=%28%5Cfrac%7B5%7D%7B2%7D%29%5Cfrac%7B2%7D%7B5%7D%28x%29%3D%28%5Cfrac%7B5%7D%7B2%7D%296)
![x=15](https://tex.z-dn.net/?f=x%3D15)
therefore
Nico, Raj and Sandra are correct