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Y_Kistochka [10]
3 years ago
7

Write the equation of a line perpendicular to 5x - 7y =-6 that passes through the point (-5,6)

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

9514 1404 393

Answer:

  7x +5y = -5

Step-by-step explanation:

You can find the perpendicular line by swapping the x- and y-coefficients, and negating one of them. The new constant can be found by using the given point.

  7x +5y = 7(-5) +5(6) = -5

The perpendicular line through (-5, 6) is ...

  7x +5y = -5

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The graph of a 10th-degree polynomial must cross the x-axis exactly once? True or False?
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The sum of the squares of two numbers is 18. the product of the two numbers is 9. find the numbers.
zhuklara [117]
A graph shows the two numbers are either (3, 3) or (-3, -3).

4 0
3 years ago
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Pls helpppppppppppppp
OLEGan [10]

Answer/Step-by-step explanation:

The following steps to solve equation given by join are shown below including the property of numbers applied for each reasons:

4(2a + 3) = -3(a - 1) + 31 - 11a ----› Given

Apply the distributive property to open the parentheses

4*2a + 4*3 = -3*a -3*-1 + 31 - 11a

8a + 12 = -3a + 3 + 31 - 11a ----› Distributive property

Combine like terms together

8a + 12 = 3 + 31 -3a - 11a

8a + 12 = 34 - 14a ---› Combining like terms

Add 14a to both sides

8a + 12 + 14a = 34 - 14a + 14a

22a + 12 = 34 ----› Addition property

Subtract 12 from both sides

22a + 12 - 12 = 34 - 12

22a = 22 ----› subtraction property of equality

Divide both sides by 22

22a/22 = 22/22

a = 1 ----› Division property of Equality

7 0
3 years ago
Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
Mademuasel [1]

Answer:- a.The given expression is equivalent to  \frac{x^{10}y^{14}}{729}



Given expression:- [\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}

=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}

=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}

=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}

=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}

=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}

Thus a. is the right answer.


6 0
3 years ago
Read 2 more answers
Add 6 and (-4)<br> Add (-8) and (-14)<br> Add (-12) and (+5)
mina [271]
6 + (-4) —> 6 - 4 = 2
(-8) + (-14) —> (-8 + (-14)) —> -(8+ 14) —> -(22) = -22
(-12) + 5 —> (-12 + 5) —> -(12-5) —> -(7) = -7
6 0
3 years ago
Read 2 more answers
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