Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min
Given:
The height of a golf ball is represented by the equation:
To find:
The maximum height of of Anna's golf ball.
Solution:
We have,
Differentiate with respect to x.
For critical values, 
.
Differentiate y' with respect to x.
Since double derivative is negative, the function is maximum at .
Substitute in the given equation to get the maximum height.
Therefore, the maximum height of of Anna's golf ball is 6.25 units.
Answer: B= A/(C+D)
Step-by-step explanation:
A = B(C+D)
Divide each side by B
A/B= C+D
Reciprocate both sides
B/A = 1/(C+D)
Now multiply each side by A
B = A/(C+D)
Answer:
The answer is 
Step-by-step explanation:
Answer:
z=-3
Step-by-step explanation:
