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expeople1 [14]
3 years ago
14

A bookstore pays $4.50 for a novel. The percent of markup is 45%. Find the novel's selling price. 55 TE OME TELE mm​

Mathematics
1 answer:
MArishka [77]3 years ago
8 0

Answer:

Selling price= $6.53

Step-by-step explanation:

Giving the following information:

A bookstore pays $4.50 for a novel. The percent of markup is 45%.

<u>To calculate the selling price, we need to use the following formula:</u>

Selling price= purchase price*(1 + mark up percentage)

Selling price= 4.5*1.45

Selling price= $6.53

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22, 23, 23, 24, 20, 8<br> What is the most appropriate measure of center?
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Answer:

In this data set, the <u>number 8 is an outlier. </u>

<u> An outlier is a value that is far away from the rest of the numbers </u>(either a lot smaller or a lot greater).

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<u> The mean will not be accurate because the outlier will make it smaller than what is actually being represented in all of the numbers but one.</u>

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6 0
4 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

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Answer:

932.8

Step-by-step explanation:

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The price of an item is p dollars. The store owner decides to mark this price up by 35%. Which expression correctly describes th
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Answer:

The answer is 135p.

Step-by-step explanation:

I hope this helps! Have a great rest of your day!

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