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Sati [7]
3 years ago
7

Can somebody please help me with this question

Mathematics
1 answer:
skad [1K]3 years ago
3 0

Answer:

Step-by-step explanation:

Provided PNWL is a parallelogram

PW = 2PM = 2(9) = 18

m∠PNW = m∠WLP = 144°

PL = NW = 12

m∠NPL = 180 - 144 = 36°

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What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
spayn [35]

Answer: 6,8 and 10

Step-by-step explanation:

To find the length , all we need to find is the distance between each point ,

the formula for calculating distance between two points is given by :

D = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

Let the points be :

A ( -5,-1)

B(-5,5)

C(3,-1)

Calculating the length AB , we have

D1 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

D1 = \sqrt{(-5+5)^{2}+(5+1)^{2}}

D1 = \sqrt{36}

D1= 6

Calculating the length AC , we have

D2 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

D2 = \sqrt{(3+5)^{2}+(-1+1)^{2}}

D2 = \sqrt{64}

D2 = 8

Calculating the length BC , we have

D3 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

D3 = \sqrt{(3+5)^{2}+(-1-5)^{2}}

D3 = \sqrt{100}

D3 = 10

Therefore ,the length of the sides of the triangle are 6,8 and 10

3 0
3 years ago
The populations of termites and spiders in a certain house are growing exponentially. The house contains 120 termites the day yo
zysi [14]

Answer:

in order to triple the inicial population of spiders, will take 50395 days

Step-by-step explanation:

we can define the termite population function as T(t) and the one for spiders as S(t) , where t represents time measured in days

since both have and exponencial growth

T(t)= a*e^(b*t)

S(t)= c*e^(d*t)

1) when the day the person moves in , t=0 and T(0)= 120 termites

T(0) = a*e^(b*0) = a = 120

2) after 4 days , t=4 and  the house contains T(4) = 210 termites

T(4)= 120*e^(b*4) = 210 → 4*b = ln (210/120) → b = (1/4)* ln(210/120)= 0.14

therefore

T(t) = 120*e^(0.14*t)

3) 3 days after moving in , t=3, there were T(3) = 120*e^(0.14*3)=182.63≈ 182 termites . The number of spiders is half of the number of termites → S(3) = T(3) * 1 spider/ 2 termites  =91.31 spiders ≈ 91 spiders

4) after 8 days of moving in , t=8, there were T(8) = 120*e^(0.14*8)=367.78≈ 368 termites . The number of spiders is 0.25 times the number of termites → S(8) = T(8) * 1 spider/ 4 termites =91.94 spiders   ≈ 92 spiders

from

S(t)= c*e^(d*t) → d = ln [S (tb)/S (ta) ] / (tb-ta)

therefore d = ln [ S(8)/S(3) ] / (8 - 3 ) = 2.18*10^-5

in order to triple the initial population

S(t3) = 3 *S(0) = 3*[c*e^(d*0)] = 3*c

S(t3) = c*e^(d*t3) = 3* c → t3 = ln(3) / d = 50395 days

5 0
3 years ago
The speeds of cars on a given i street we are normally distributed with a mean of 72 miles per hour and a standard deviation of
Ostrovityanka [42]

Answer: 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

Step-by-step explanation:

Let X be a random variable that represents the speed of the drivers.

Given: population mean : M = 72 miles ,

Standard deviation: s= 3.2 miles

The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:

P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278

Hence, 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

3 0
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3 years ago
What’s the answer to this question. <br> Simple correct answers
Sophie [7]

Answer:

1st one

Step-by-step explanation:

5 0
3 years ago
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