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2 years ago

Helpp please!.......

Mathematics

1 answer:

Shalnov [3]2 years ago

3 0

Does it have any more information??

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Without expanding determinants, Prove that

sasho [114]

Answer:

To prove???

Step-by-step explanation:

i have proved this

6 0

3 years ago

If R is the set of all integers with absolute value less than 10, A is its subset containing all natural numbers less than 10 an

Elza [17]

Answer:

See explanation

Step-by-step explanation:

1. R is the set of all integers with absolute value less than 10, thus

$R=\{a\in \mathbb{Z}\ :\ |a|$

2. A is its subset containing all natural numbers less than 10, thus

$A\subset R\\ \\A=\{b\in \mathbb{N}\ :\ b$

3. B is the set of all integer solutions of inequality 2x+5<9 that are less than 10 by absolute value (and therefore, it is also a subset of R). First, solve the inequality:

$2x+5$

Thus,

$B\subset R\\ \\B=\{c\in \mathbb{Z}\ :\ 2c+5$

See the diagram in attached diagram.

Note that

$A\cup B=R\\ \\A\cap B=\{1\}.$

4 0

3 years ago

The sum of three numbers is 97. The third number is 2 times the second. The second number is 9 less than the first. What are the

inn [45]

Answer:

The numbers are 26.5, 53 and 17.5.

Step-by-step explanation:

97=x+(x-9)+2x

97+9=4x

106/4=4x/4

x= 26.5

x-9 = 17.5

2x= 53

8 0

3 years ago

Joey is creating a rectangular garden. The garden is 9 feet long and 7 feet wide. Joey calculated he needs feet of fencing to cl

Crazy boy [7]

Answer:

Amount of fencing: 32 feet

Amount of soil: 63 square feet

Step-by-step explanation:

Fencing: In a rectangle, the opposite side is the same length. So we do:

9+7+9+7 = 32 feet

Soil: The soil is the area. Area is equal to length times width. Length is 9 and width is 7, so we do:

9 x 7 = 63 feet squared

8 0

3 years ago

How to solve this :') please help

blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

$\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\$

Use $\cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1$

$\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}$

7 0

2 years ago