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Snezhnost [94]
3 years ago
7

If a^2=b^2, does a=b? Explain and justify your answer.

Mathematics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

  not necessarily

Step-by-step explanation:

Taking the square root of both sides, you have ...

  ±a = ±b

Those four cases resolve to two unique cases:

  a = ±b

The given equation will be true if a = b or if a = -b. If a and b are constrained to have the same sign, then a=b is the only solution.

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What is the solution to -1.6 > b - (-4.4)
Bezzdna [24]

Answer:

B

Step-by-step explanation:

-1.6 > b - (-4.4) =

-1.6 > b + 4.4 ( - - cancels to become a +)

move 4.4 to left by subtracting 4.4 from both sides

-1.6 - 4.4 > b + 4.4 - 4.4 =

-6.0 > b + 0 =

-6.0 > b

6 0
2 years ago
Read 2 more answers
F) 16 - p = 12 <br> g) 18 - 2p = 6<br> h)p2+ 4 = 9 <br> i)p4- 3 = 1<br> **MUST SHOW YOUR WORK**
mestny [16]
f) 16 - p = 12 minus 12
4 - p = 0 plus p
p = 4
g) 18 - 2p = 6 divide by -2
-9 + p = -3 plus 9
p = 6
h) p x 2 + 4 = 9 divided by 2
p + 2 = 4.5 minus 2
p = 2.5
i) p x 4 - 3 = 1 plus 3
p x 4 = 4 divided by 4
p = 1
3 0
3 years ago
Alice is riding the train to her job in Paris, France. She accidentally purchased a ticket for zone 4, but she is
stepan [7]

Answer:

3005 euro is the answer

7 0
2 years ago
Rework problem 35 from the Chapter 2 review exercises in your text, involving auditioning for a play. For this problem, assume 9
sweet-ann [11.9K]

Answer: 1) 6300 ways

2) 2520 ways

3) 0.067

Step-by-step explanation:

For this problem, assume 9 males audition, one of them being Winston, 5 females audition, one of them being Julia, and 6 children audition. The casting director has 3 male roles available, 1 female role available, and 2 child roles available.

How many different ways can these roles be filled from these auditioners?

Available: 9M and  5F and 6C

Cast: 3M and 1F and  2C

As it is not ordered: C₉,₃ * C₅,₁ * C₆,₂

C₉,₃ = 9!/3!.6! = 84

C₅,₁ = 5!/1!.4! = 5

C₆,₂ = 6!/2!.4! = 15

C₉,₃ * C₅,₁ * C₆,₂ = 84.5.15 = 6300

How many different ways can these roles be filled if exactly one of Winston and Julia gets a part?

2 options Winston gets or Julia gets it:

1) Winston gets it but Julia no:

8 male for 2 spots

4 females for 1 spot

6 children for 2 spots

C₈,₂ * C₄,₁ * C₆,₂

C₈,₂ = = 8!/2!.6! = 28

C₄,₁ = 4!/1!.3! = 4

C₆,₂ = 6!/2!.4! = 15

C₈,₂ * C₄,₁ * C₆,₂ = 28.4.15 = 1680

2) Julia gets it but Winston does not

8 male for 3 spots

1 female for 1 spot

6 children for 2 spots

C₈,₃ * C₆,₂

C₈,₃ = 8!/3!.5! = 56

C₆,₂ = 6!/2!.4! = 15

C₉,₃ * C₆,₂ = 56.15 = 840

1) or 2) = 1) + 2) = 1680 + 840 = 2520

What is the probability (if the roles are filled at random) of both Winston and Julia getting a part?

8 male for 2 spots

1 female for 1 spot

6 children for 2 spots

C₈,₂ * C₆,₂

C₈,₂ = = 8!/2!.6! = 28

C₆,₂ = 6!/2!.4! = 15

C₈,₂ * C₆,₂ = 28.15 = 420

p = 420/6300 = 0.067

6 0
3 years ago
The White Russian cocktail contains vodka, Tia Maria and milk in the ratio of 5:2:3. To make the cocktail for a party the barman
stellarik [79]

Answer:

1) 600cm^3            2) 10 glasses

Step-by-step explanation:

x = total amount in ml

(3/10)x = 180ml (MILK)

x = 600ml

(2/10)600 = 120ml (TIA MARIA)

(1/2)600 = 300ml (VODKA)

<em>1) 600cm^3</em>

<em>2) 600ml : 60ml = 10 (GLASSES)</em>

6 0
2 years ago
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