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daser333 [38]
2 years ago
15

The daily profit, P, of a local bakery can be calculated using the formula P=m-(250+4h) when employees work a total of h hours a

nd the bakery receives m dollars. Write an equation to the calculate the amount of money, m, the bakery should receive if the desired profit is $415.
Mathematics
1 answer:
qwelly [4]2 years ago
5 0

Answer:

m=665+4h

Step-by-step explanation:

Profits of the local bakery is given by

P=m-(250+4h)

where

m = Amount of money to be received

P = Profit

h = Number of hours worked

Now P = $415

So,

P+(250+4h)=m\\\Rightarrow m=P+250+4h\\\Rightarrow m=415+250+4h\\\Rightarrow m=665+4h

The equation to calculate the amount of money, m, the bakery should receive if the desired profit is $415 is m=665+4h.

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A game decreased in price by 1/5. After the reduction it was priced at £48. What was the original price of the game?
Agata [3.3K]

Answer:

1/5 is equal to 20% so you multiply 48 by .20 and you get 9.6 and your take 9.6 and add it to 48. your answer will be 57.6

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3 years ago
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What is the area of the figure?<br><br><br><br> 20 m2<br> 24 m2<br> 32 m2<br> can't be determined
nikdorinn [45]
I think the answer is 32m2
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2 years ago
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For questions 7 – 8, use the following functions: f(x) = 4x + 3x g(x) = 2x – 5 7. Find (f + g)(x). 8. Find (f – g)(x).
densk [106]

Answer:

7) (f+g) (x) = 4^x + 5x -5

8) (f-g) (x) = 4^x + x - 5

Step-by-step explanation:

7)  Find (f +g)(x)

(4^x + 3x + 2x - 5)

(4^x + 5x -5)

(f+g) (x) = 4^x + 5x -5

8) Find (f-g)(x)

(4^x + 3x - 2x - 5)

(4^x + x - 5)

(f-g) (x) = 4^x + x - 5

8 0
3 years ago
Please show me 3+2 (2x - 4) and can you please show the work?
Julli [10]

Answer:

4x -5

Step-by-step explanation:

3+2 (2x - 4)

Distribute

3 + 2*2x - 2*4

3+4x - 8

Combine like terms

4x +3-8

4x -5

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2 years ago
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Your goal is to create a college fund for your child. Suppose you find a fund that offers an APR of 4 %. How much should you dep
Alisiya [41]

Answer:

$701.12

Step-by-step explanation:

Before doing the computing, notice that if we increase an amount D in,say,  r%, it means that the new amount obtained is D+r% of D = D+(r/100)D = D(1+r/100).

That is to say, increasing an amount D in r% is equivalent to multiplying it by (1+r/100)

Taking into account that <em>APR stands for Annual Percentage Rate</em>, the amount we deposit will be increased 4% each year.  

Generally, in this kind of loans <em>the percentage is prorated monthly</em>. That is to say, <em>the money you have in the account will be increased in (4/12)%= 0.3333% each month. </em>

Let D be the amount we are going to deposit each month.

After the month 1 we will have the money increased in 0.3333% plus the new deposit

D(1+\frac{0.3333}{100})+D=D(1+1.0033)

After the month 2 we will have the money we already had increased in 0.3333% plus the new deposit D

D(1+1.0033)(1.0033)+D=D(1.0033+1.0033^2)+D=D(1+1.0033+1.0033^2)

After the month 3 we will have, for the same reason,

D(1+1.0033+1.0033^2+1.0033^3)

It can be noticed then, that after 18 years (96 moths) we will have an amount in the fund of

D(1+1.0033+1.0033^2+...+1.0033^{96})

If we call  

S=1+1.0033+1.0033^2+...+1.0033^{96}

then

1.0033S=1.0033+1.0033^2+...+1.0033^{96}+1.0033^{97}

Subtracting the equations

S-1.0033S=1-1.0033^{97}\Rightarrow S(1-1.0033)=1-1.0033^{97}

and we have

S=\frac{1-1.0033^{97}}{1-1.0033}=114.10298

So, after 18 years the amount in the fund will be

114.10298D

If we want this amount to be $80,000 then 114.10298D=80,000

D=\frac{80,000}{114.10298}\approx \$ 701.12

So, the money we would have to deposit each month in a fund with an APR of 4% to accumulate $80,000 in 18 years, is

\boxed{D=\$701.12}

5 0
3 years ago
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