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puteri [66]
2 years ago
6

A student multiplied 48×42 instead of 48 by 24. By how much was is his answer off​

Mathematics
1 answer:
nata0808 [166]2 years ago
5 0

Answer:

864

Step-by-step explanation:

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Use the equation y=-3x if the x-value is 2 1/3
disa [49]

Answer:

y=-7

Step-by-step explanation:

Multiply -3 times 2 1/3

Hope this helps!

5 0
3 years ago
Read 2 more answers
Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1
GalinKa [24]

Answer:

-2,\ -1,\ -\dfrac{1}{2},\ 3.

Step-by-step explanation:

Consider polynomial 2x^4+x^3-14x^2-19x-6.

If x=-2 is its zero, then you can divide the polynomial 2x^4+x^3-14x^2-19x-6 by x+2 and get

2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).

If x=-1, then the polynomial 2x^4+x^3-14x^2-19x-6 can be rewritten as

2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).

The quadratic polynomial has roots

x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.

Then the polynomial 2x^4+x^3-14x^2-19x-6 has zeros -2,\ -1,\ -\dfrac{1}{2},\ 3.



7 0
3 years ago
What is the inverse matrix
Anuta_ua [19.1K]

Answer:

The inverse of a square matrix A, denoted by A-1, is the matrix so that the product of A and A-1 is the Identity matrix.

Step-by-step explanation:

3 0
3 years ago
Phyllis invested $11,500, a portion earning a simple interest rate of
Cerrena [4.2K]

Answer:

He invested $8500 with rate 3 1/5%

He invested $3000 with rate 3%

Step-by-step explanation:

* <em>Lets revise the rule of the simple interest</em>

- Simple interest I = PRT, where P in the money invested, R is the

 interest rate and T is the time of investment

- Phyllis invested $11,500

- A portion earning a simple interest rate of 3 1/5% (3.2%) per year

- The rest earning a rate of 3% per year

- After one year the total interest earned on these investments

 was $362.00

- We need to find the amount of money invested in each rate

* Assume that he invested $x with rate 3 1/5% and $y with rate 3%

∵ He invested $11,500 in both rates

∴ x + y = 11,500 ⇒ (1)

∵ He invested $x with 3 1/5%

∵ P = $x

∵ R = 3.2/100 = 0.032

∵ T = 1

∴ I_{1}=x(0.032)(1)

∴ I_{1}=0.032x

∵ He invested $y with 3%

∵ P = $y

∵ R = 3/100 = 0.03

∵ T = 1

∴ I_{2}=y(0.03)(1)

∴ I_{2}=0.03y

∵ The total interest was $362.00

- The total interest = I_{1} + I_{2}

∴ 0.032x + 0.03y = 362.00 ⇒ (2)

<em>We have system of equations</em>

x + y = 11,500 ⇒ (1)

0.032x + 0.03y = 362.00 ⇒ (2)

Multiply equation (1) by -0.03 to eliminate y

-0.03x - 0.03y = 345 ⇒ (3)

Add equations (2) and (3)

0.002x = 17

Divide both sides by 0.002

x = 8500

Substitute the value of x in equation (1)

8500 + y = 11,500

Subtract 8500 from both sides

y = 3000

* He invested $8500 with rate 3 1/5%

* He invested $3000 with rate 3%

7 0
3 years ago
А ?B xº 73° What is the value of x?<br>I just need angle a and x​
Rzqust [24]
X = 107
a straight line is 180 degrees and we are given one angle so just do 180-173.
8 0
3 years ago
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