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Brrunno [24]
3 years ago
12

CAN SOMEONE HELP ME PLS ASAP

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
Answer:

B


Explanation:

10x1=10

(not sure haven’t done this in a very long time)
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The diameter of a circle is 28 inches what is the circle's area?<br><br> use 3.14 for pi
jolli1 [7]

Answer:

615.75216....

Step-by-step explanation:

The formula is A = π * (ø/ 2)^2

A = Circle area

π = Pi = 3.14

ø = Circle diameter

A= 3.14  (28/2)^2

5 0
3 years ago
Read 2 more answers
Help me Please! Find the volume and surface area for all.
HACTEHA [7]

Answer:

V =41.41³

A = 94.41²

----

V =225.16³

SA =283.25²

----

V = 64³

SA =113.32²

----

V =433.33³

SA = 378.57²

Step-by-step explanation:

Picture 2 = a = 1/2 base = 3.5 x 3.5 = 12.25  b= 5 x 5 = 25

c²= a² + b² = 3.5² + 5²

c ²= √12.25 + √25

c ²= √ 37.5 = 6.12372435696

c ² = 6.1237   missing side

Picture 1 + 2  formula SA = bh + (s1 + s2 + s3)H

V =  V= 1/2 b x h  h x SA

Picture 3 + 4  formula SA= a²+ 2a   a² / 4 + h²    V= a²  h/3

5 0
3 years ago
Please help me with this math question​
scZoUnD [109]

Answer:

<h2>d : e : f = 4 : 3 : 6</h2>

Step-by-step explanation:

\bold{METHOD\ 1}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\to d=\dfrac{4}{3}e\\\\\text{Substitute it and}\ f=2e\ \text{to the ratio}\ d:e:f:\\\\\dfrac{4}{3}e:e:2e\qquad\text{cancel}\ e\\\\\dfrac{4}{3}:1:2\qquad\text{multiply by 3}\\\\\huge\boxed{4:3:6}

\bold{METHOD\ 2}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\qquad\text{divide both sides by}\ e\neq0\\\\\dfrac{d}{e}=\dfrac{4}{3}\to d:e=4:3\\\\2e=f\qquad\text{divide both sides by 2}\\\\e=\dfrac{f}{2}\to e=\dfrac{1}{2}f\qquad\text{divide both sides by}\ f\neq0\\\\\dfrac{e}{f}=\dfrac{1}{2}\to e:f=1:2\\\\\text{We have}\ d:e=4:3\ \text{and}\ e:f=1:2.

\text{We know}\ \dfrac{1}{2}=\dfrac{1\cdot3}{2\cdot3}=\dfrac{3}{6}\\\\\text{threfore}\ e:f=3:6\\\\\text{Now we have}\\\\\left\begin{array}{ccc}d:e=4:3\\e:f=3:6\end{array}\right\}\large{\boxed{d:e:f=4:3:6}}

6 0
3 years ago
Achemistry journal requires that all new research papers be peer reviewed by other scientists before they are published. This
gavmur [86]

Answer:

The reviewers can determine the experiment's feasibility.

Step-by-step explanation:

First of all this isn't math but the answer is between A & B, typically it is checked for mistakes that could lead to it being flawed. From this It is most likely A due to it being a paper and not an actual experiment, they would be looking for if it COULD happen, not if it WILL happen. They wouldn't add their own findings to someone elses paper, and it typically isn't for funding.

3 0
3 years ago
The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive
gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p}  = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students  believe that they will find a job immediately after graduation= 3099

Then,  \hat{p}=\dfrac{3099}{3597}\approx0.8616

We know that , Critical value for 99% confidence interval = z*=2.576  (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}

0.8616\pm (2.576)\sqrt{0.0000331513594662}

\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

4 0
3 years ago
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