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3 years ago

6 + p <4 solve and graph

Mathematics

2 answers:

Artyom0805 [142]3 years ago

7 0

Answer:

P2 + 2P - 24

Step-by-step explanation:

guajiro [1.7K]3 years ago

6 0

Answer:

harjot sinfh answer hai bro is

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Simplify this expression 4X^2y^3 x 2x^3y^4

Lena [83]

Answer:

8^5^7

Step-by-step explanation:

Multiply the numbers:

4X^2 y^3 x 2x^3 y^4

8^2 ^3 ^3 ^4

Combine Exponents:

8^2 ^3 ^3 ^4

8^5 ^3 ^4

8^5 ^3 ^4

8^5 ^7

7 0

2 years ago

Consider a graph of the equation y = −3x + 4. What is the y-intercept?

Murrr4er [49]

Y = -3x + 4
In y = mx + b form, the y intercept will be in the b position.

y = mx + b
y = -3x + 4......so ur y intercept is 4.....or (0,4)

just so u know....in y = mx + b form, the slope will be in the m position....so ur slope would be -3

5 0

3 years ago

Read 2 more answers

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

Shannon drew the line of best fit on the scatter plot shown below:

N76 [4]

Using the points (0,14) and (10,0), the gradient of the line is (14-0)/(0-5) which simplifies to -7/5.

From these points, we can also see that when the x value is zero, the y value is 14. Therefore the y-intercept is 14.

We can then put this into the equation of a straight line, y=mx+c:

y = (-7/5)x + 14

6 0

2 years ago

Read 2 more answers

Susan had a $10 coupon for the purchase of any time item. She bought a coat that was on sale for

gulaghasi [49]

The original price is 260

2*125+10 please mark me brainliest

7 0

3 years ago