Answer:
(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0
(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0
Step-by-step explanation:
(a) when i = 2, the expected number of played games will be:
E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] = 4p²-4p+2-6p²+6p = -2p²+2p+2.
If p = 1/2, then:
d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.
(b) when i = 3;
E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]
Simplification and rearrangement lead to:
E(X) = 6p⁴-12p³+3p²+3p+3
if p = 1/2, then:
d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10
Therefore, E(X) is maximized.
Answer:
The slope is -7/4
Step-by-step explanation:
∵ 7x + 4y = 10
∵ y = mx + c ⇒ where m is the slope of the line
∴ Re-arrange the equation
∴ 4y = 10 - 7x ⇒ ÷4
∴ y = 10/4 - (7/4) x
∴ y = 5/2 - (7/4) x
∴ The slope is -7/4
The sequence of all odd numbers between 1 and 11 (both inclusive) is
1,3,5,7,9,11
This is an arithmetic sequence with common difference of d=2
The first term is a₁=1.
The number of the term 11 (without counting) is found from
1 + (n-1)*2 = 11
1 + 2n - 2 = 11
2n -1 = 11
2n = 12
n = 6
The sum of the first n terms of an arithmetic sequence is
Therefore, the sum of the sequence is
S₆ = [6*(1 + 11)]/2
= (6*12)/2
= 36
Answer: 36
Answer:
QUESTION:
which experimental probability from coach nelson's experiment equals the theorectical probability? what is this probability?
ANSWER:
This will explain everything to you.
https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-probability-statistics/cc-7th-theoretical-and-experimental-probability/v/comparing-theoretical-to-experimental-probabilites
Step-by-step explanation:
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Answer:
The ratio children to adult is 9:3
In reduced form, the ratio is 3:1
