7 is the right answer(please rate 5.0 stars so i can help other people out thanks)
Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy = 
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) =
- 
⇒ x + iy = 
⇒ x + iy =
[ ∵
]
⇒ x + iy =
⇒ x + iy =
⇒ x + iy =
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
Answer:
1st number: 22
2nd number: 16
3rd number: 64
Step-by-step explanation:
x + y + z = 102
x = 6 + y
z = 4y
plug that in!
(6 + y) + y + (4y) = 102
get rid of the parenthesis (I added them so you could see what I was replacing) and add like terms.
6 + 6y = 102
move 6 to the other side.
6y = 96
y = 16
now that you know one number, you can solve the equations for the rest!
x = 6 + (16)
z = 4(16)
__________________________________________________________
x = 22
y = 16
z = 64
Answer:
y=2x+17
Step-by-step explanation:
y-y1=m(x-x1)
y-1=2(x-(-8))
y-1=2(x+8)
y=2x+16+1
y=2x+17