Mu=80, sigma=39, X=85
Z=(X-mu)/sigma = 5/39=0.128=0.13
P(X<=85)= 0.5517 (from Z-table)
so, P(X>85)=1-0.5517=0.4483 approx. thats 44.8% probability.
If Kyle starts with $600 and wants to end with (at least) $300 She can withdraw up to $600−$300=$300
If he withdraw 20$/ week the 300 will last for 300/20 = 15 weeks
Relationship is going to work out so 72728
Answer:
A. 5(-20)
Step-by-step explanation:
Since she repeatedly withdrawals money, the answer would be negative, so you can say that the other answers are definitely wrong.
Hope this helps :)