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uranmaximum [27]
3 years ago
12

Helpppppo me with this pleaseeee

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Answer:

I think a but I am not 100 percent sure

Step-by-step explanation:

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Solve By Factoring: 7x^2+6x-3=0
Allushta [10]

Answer:

x= -3-sqr30/7

Step-by-step explanation:

3 0
3 years ago
Determine if the triangles are congruent by HL, SAS, SSS, AAS, or
Tom [10]
Asa. the side is in the middle of the angles
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3 years ago
Carrie likes to buy t-shirts at the local clothing store. The shirts cost $9.95 each. If she buys 25 t-shirts, how much money wi
DerKrebs [107]
Carrie will spend 248.75 on 25 t-shirts. Multiply $9.95 by 25.
3 0
3 years ago
A family is thinking about buying a new house
Rom4ik [11]

Answer:

a.) 1908.30

b.) 96373.15

c.)302491.15

unrounded answers below

Step-by-step explanation:

The amount that is to be loaned out is 380000-110000=270000

The effective montly rate is .07/12=.005833333

a.)

270000=x(\frac{1-(1+.005833333)^{-(25*12)}}{.005833333})=1908.303833

b.)

use what is called the prospective method (the outstanding loan balance at time n is equal to the present value of the remaining payments)

1908.303833(\frac{1-(1+.005833333)^{-(25*12-20*12)}}{.005833333})=96373.14775

c.)

total paid= 1908.303833*12*25=572491.1499

amount of loan: 270000

Total interest paid:

572491.1499-270000=302491.1499

3 0
3 years ago
Check whether the function yequalsStartFraction cosine 2 x Over x EndFraction is a solution of x y prime plus yequalsnegative 2
Jobisdone [24]

The question is:

Check whether the function:

y = [cos(2x)]/x

is a solution of

xy' + y = -2sin(2x)

with the initial condition y(π/4) = 0

Answer:

To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.

Let us do that.

y = [cos(2x)]/x

y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]

Now,

xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x

= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)

= -2sin(2x)

Which is the right hand side of the differential equation.

Hence, y is a solution to the differential equation.

6 0
4 years ago
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