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uranmaximum [27]
3 years ago
12

Helpppppo me with this pleaseeee

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Answer:

I think a but I am not 100 percent sure

Step-by-step explanation:

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Explain why f(x) =√2+x - √2/x, is not continuous at x = 0.<br> Picture provided below.
IrinaK [193]

Answer: A

Step-by-step explanation:

If you put 0 in for x, then you would be dividing by 0. Dividing by 0 is always undefined.

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3 years ago
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What is the answer to -7/24 - (-5/8)? Show work please...
Nitella [24]
Answer <span>-7/24 - (-5/8) = 1/3</span>
8 0
3 years ago
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What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
If two trucks leave a given city on highways making an angle of 132 degrees with one another, traveling at 45 and 55 miles per h
Law Incorporation [45]

Answer:

183 miles to the nearest mile.

Step-by-step explanation:

Distance =Speed X Time

Distance of Truck B from point A=45 X2 =90 miles

Distance of Truck C from point A=55 X2 =110 miles

Angles between them, BAC=132°

We want to find the Distance BC denoted by a between the trucks.

Using Cosine Rule,

a²=b²+c²-2bcCos A

=90²+110²-(2X90X110XCos132°)

=33448.79

a=√33448.79

BC=182.89 miles

The distance between the trucks is 183 miles to the nearest mile.

3 0
3 years ago
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What is 6900g converted to kg???
stich3 [128]
1000 g=1kg
to convert to kg
1kg/1000g=conversion factor
multiply
6900g times 1kg/1000g
grams cancel
6.9 kg
4 0
3 years ago
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