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2 years ago

Question 7 of 7 (1 point) Question Attempt 3 of 3

Mathematics

1 answer:

Neporo4naja [7]2 years ago

3 0

Answer:

To divide, use / instead of \.

Examples: 1+2, 1/3+1/4, 2^3 * 2^2

(x+1)(x+2) (Simplify Example), 2x^2+2y x=5, y=3 (Evaluate Example)

y=x^2+1 (Graph Example), 4x+2=2(x+6) (Solve Example)

Step-by-step explanation:

example

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The populations and areas of four states are shown. A 3-column table has 4 rows. The first column has entries State A, State B,

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Answer:

Step-by-step explanation:

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2 years ago

TRUE OR FALSE: The solution to the equation 3y – 4 = 6 - 2y is -10.

anygoal [31]

Answer:

false your answer would be 2

Step-by-step explanation:

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3 years ago

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If UV ≅ UX and WX=23, what is VW?<br><br> VW =

KiRa [710]

<h2>Answer: </h2>

The length of VW is 23°

<h2>Step-by-step explanation: </h2><h3>Known : </h3>

UV = UX
WX = 23

<h3>Asked : </h3>

VW = ?

<h3>Solution : </h3>

Since the UV line and UX line has the same length, so the VW line should have the same length as the WX line.

VW = WX

23 = 23

<h3>Conclusion : </h3>

The length of VW is 23°

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Simplify the expression. Write your answer as a power.

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w^4

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If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num

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Step-by-step explanation:

$x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right$

$\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right$

$\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}$

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