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3 years ago

15

Which of the following is closest to the distance that the tip of the hand travels as it moves from

1 answer:

Gwar [14]3 years ago

8 0

Answer:H

Step-by-step explanation:

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Question 11 what is the naswer please fast

Novay_Z [31]

D
They are the same length :)

6 0

2 years ago

Find the values for c and d

baherus [9]

Answer:

c=-5

d=1

Step-by-step explanation:

$(cy^2)(4y^d)=-20y^3$

I'm going to reorder the left-hand side. Multiplication is commutative.

$(4c)(y^2y^d)=-20y^3$

Since the bases are the same in $y^2y^d$ and the operation is multiplication, I'm going to add the exponents giving me:

$4cy^{2+d}=-20y^3$

So this implies we have two equations to solve:

$4c=-20$ and $2+d=3$

So the first equation can be solved by dividing both sides by 4 giving you $c=-5$ .

The second equation can be solved by subtracting 2 on both sides giving you $d=1$ .

6 0

3 years ago

Solve the question (equation) 0.3r=96

Alika [10]

The correct and best answer is r=320 because you have to divide both sides by 0.3

6 0

3 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

A sample of marble has a volume of 6 cm3 and a density of 2.76 g/cm3. What is its mass?

Drupady [299]

Answer:

$16.56\ g$

Step-by-step explanation:

we know that

The density is equal to the mass divided by the volume

Let

x-----> the mass of marble

y----> the volume of marble

z----> the density of marble

$z=\frac{x}{y}$

in this problem we have

$y=6\ cm^{3}$

$z=2.76\ g/cm^{3}$

substitute and solve for x

$2.76=\frac{x}{6}$

$x=2.76*6=16.56\ g$

3 0

3 years ago

Read 2 more answers