Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Whenever you solve an equation with a single variable you need to isolate the variable by itself on one side of the equal sign. Just be sure that whatever operations you perform on one side you perform on the other sides as well.
62x=1 divide both sides by 62
x=1/62
Answer:
3. 
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo
My answer;
We use oder of operation to solve this question
We have BEDMAS, which means:
In 4 answer, only answer is correct:
= 
(3*25 +4)
= (79 + 4)
= *83
= 8*83
= 664
Step-by-step explanation:STEP 1: Draw two straight, intersecting tangent lines onto the circle. The lines can be completely random. However, the process will be easier if you make them roughly square or rectangular.
STEP 2: Translate both of the lines to the other side of the circle. You will end up with four tangent lines forming a parallelogram or a rough rectangle.
STEP 3: Draw the diagonals of the parallelogram. The point where these diagonal lines intersect is the circle's center.
STEP 4: Check the accuracy of the center with a compass. The center should be on target as long as you didn't slip while translating the lines or when drawing the diagonals. Feel free to erase the parallelogram and diagonal lines.
