Ask question

Ask question

All categories

2 years ago

15

A wallet containing $40 has three times as many $1 notes as $5. Find the number of each kind. (Pls give answer urgently needed w

ith working)

1 answer:

lisov135 [29]2 years ago

8 0

X=one dollar
y=5 dollar

x=3y
1x+5y=40
3y+5y=40
8y=40
divide 8
y=5
x=3y
x=3(5)
x=15

15 one dollars
5 five dollars

You might be interested in

A rectangle with an area of 120 in 2 has a length 8 inches longer than two times its width. What is the width of the rectangle?

nlexa [21]

width = x

length = 2x+8

area = l x w

x<span>(2x+8)</span>=120

<span><span>2<span>x^2</span>+8x−120=0 </span> </span>

<span><span><span>x^2</span>+4−60=0 </span></span>

<span><span><span>(x+10)</span><span>(x−6)</span>=0</span> </span>

<span><span>x=−10 and x=6 </span></span>

<span><span> width has to be a positive number</span></span>

Width = <span>6 </span> inches.

5 0

2 years ago

Suppose a principal amount of $2079 were invested into a simple interest account that pays an annual rate of 2.31% then the amou

Anna35 [415]

Answer:

The amount of interest earned at the end of 14 years would be $672.3486

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

In this problem, we have that:

$P = 2079, I = 0.0231, t = 14$

So

$E = 2079*0.0231*14 = 672.3486$

The amount of interest earned at the end of 14 years would be $672.3486

4 0

2 years ago

In a scalene triangle , the perimeter is 33, and the length of one side is 15, and the difference between the two other sides is

zepelin [54]

Answer:D

Step-by-step explanation:

4 0

2 years ago

4/5 divided by 1/3 ??

DochEvi [55]

Answer:

2.4

Step-by-step explanation:

3 0

2 years ago

Which matrix represents the system of equations shown below? 2x-y=-6 and x-6y=13

dezoksy [38]

Answer: D

<u>Step-by-step explanation:</u>

The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.

$\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]$

The product will result in the solution for the x- and y-values of the system.

6 0

3 years ago