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Jlenok [28]
3 years ago
9

2 cm = 7.5 m in the drawing the mall is 8.6 cm tall how tall is the actual mall

Mathematics
1 answer:
andrezito [222]3 years ago
8 0

Step-by-step explanation:

here's the answer to your question

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4) Suppose y varies inversely with the SQUARE ROOT of x.
Savatey [412]

Answer:

Variation equation: y = k/√x

constant of variation: 200

Variation Equation by plugging the value of k: y = 200/√x

Step-by-step explanation:

If y varies inversely with the SQUARE ROOT of x, then;

y = k/√x

If  x = 4, y = 100.

100 = k/√4

100 = k/2

200 = k

k = 200

Substitute into the expression

y = k/√x

y = 200/√x

7 0
3 years ago
Solve the equation of isosceles triangle and find the x​
Fantom [35]

Answer:

x = 25°

Step-by-step explanation:

2x-10°+2x-10°+100°=180°[sum of angles in a triangle ]

4x+80°=180°

4x=100°

x=25°

5 0
3 years ago
What is the purpose of simultaneous equations?
sveta [45]

Answer:

a set of two or more equations, each containing two or more variables whose values can simultaneously satisfy both or all the equations in the set, the number of variables being equal to or less than the number of equations in the set.

Step-by-step explanation:

It works because of two properties of equations: Multiplying (or dividing) the expression on each side by the same number does not alter the equation. Adding two equations produces another valid equation: e.g. 2x = x + 10 (x = 10) and x − 3 = 7 (x also = 10).

5 0
3 years ago
Find the mode of the following data for data sets a-d (Remember what the steps are for finding the mode ).Rewrite the problem as
Nitella [24]
The mode would be 17, it’s the number that appears the most. I’m not rewriting it though
6 0
3 years ago
What is the answer to(1−5q)+2(2.5q+8)
never [62]
Greetings!

Simplify the Expression.
=(1-5q)+2(2.5q+8)

Distribute the Parenthesis. 
<em>How?</em><span> Multiply the terms inside the Parenthesis by the term outside of the Parenthesis.
</span>=1*1-1*5q+2*2.5q+2*8

Combine Like Terms.
=1-5q+5q+16

=17

The Answer Is:
\left[\begin{array}{ccc}17\end{array}\right]

Hope this helps.
-Benjamin

5 0
3 years ago
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