1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lady_Fox [76]
2 years ago
6

Is 0.123 greater or is 1.23 greater? Thank you!

Mathematics
2 answers:
julia-pushkina [17]2 years ago
6 0

Answer:

1.23

Explaination:

zmey [24]2 years ago
3 0

Answer:

1.23 is greater

Step-by-step explanation:

0.123 is only a fraction of a number it’s not a whole number. 1.23 is a whole number with an extra fraction of a number so it’s greater.

You might be interested in
On which number do i put a vinculum line on 0.166666667?I WILL PUT BRAINLIST if it's useful
MAVERICK [17]

Answer:

On 6

Step-by-step explanation:

On 6 to show that it continues

6 0
3 years ago
Which graph shows a linear function?
maw [93]
That one is an absolute I can’t see the other ones
7 0
2 years ago
Dawn Dough and Dale earned different amounts $9.35,$8.52,and$8.25 dale and Doug earned about $9.00 Dawn earned exactly $1.10less
Zielflug [23.3K]

We know that the amounts earned by Dawn, Doug and Dale are from the list of numbers: $9.35, $8.52 and $8.25

We also know that Dale and Doug earned close to $9.00

And that Dawn earned $1.10 less than Dale

Let the amount earned by Dale be x

⇒ Amount earned by Dawn is x - 1.1

If we notice the list of numbers, we see that $9.35 and $8.25 differ by $1.1

Hence, Dale earned $9.35 and Dawn earned $8.25

We are now left with $8.52, which should be the amount earned by Doug. This is correct, since we also know that Doug earned close to $9.

Hence, the amounts earned are:

Dale: $9.35

Doug: $8.52

Dawn: $8.25

8 0
3 years ago
If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
Vlad [161]

Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

7 0
3 years ago
What 1x0 -p1s yyyyrr
11111nata11111 [884]
0.

anything multiplied by 0 = 0.
4 0
2 years ago
Other questions:
  • The concept of determining which reactant is limiting and which is in excess is akin to determining the number of sandwiches tha
    12·1 answer
  • Kiley had a piece of bamboo skewer that measured 14Three-fifths inches long. She wanted to cut it into toothpicks that were each
    12·2 answers
  • Need help with this question for an exam!
    15·1 answer
  • PLEASE HELP ME WITH THIS STUPID QUESTION!!!! WHAT DO I HAVE TO PUT IN THE BOX!! 30pts. Will mark brainliest!!!
    6·1 answer
  • Need help please please someone help me
    14·2 answers
  • Each dairy cow in the U.S. produces an average
    14·1 answer
  • Can someone help this is so herd.
    15·1 answer
  • Write the fraction in simplest form: 55/132 ASAP pls help me
    14·1 answer
  • it snowed 7/8 inches on Monday. on Tuesday it snowed 1/4 inches less than it did on Monday. how much did it snow on tuesday HELP
    14·2 answers
  • 2- 1/2 divided by 1 - 1/4
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!