Answer: 2, 20 dollar bills and 1, 1 dollar bill, and there is no way to use 8 coins to get 11 cents you can use 7 by using 1 nickel and 6 pennies
Step-by-step explanation:
Answer:
It would be a obtuse triangle instead
Step-by-step explanation:
By using pythagorean and theorem (a^2 + b^2 = c^2)
So it would be 13^2___2^2 + 12^2
When you square them, you get 169___4 + 144
144 + 4 = 148, which is less than 169
SO it would be 169>148
So no, not a right triangle
Answer:
8
Step-by-step explanation:
2log(x)=log(64)
By logarithms properties
log(x²)=log(64)
When you have log or ln in both sites, you delete them and...
x²=64
![\sqrt[]{x^{2} } =\sqrt{64} \\x=8](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7Bx%5E%7B2%7D%20%7D%20%3D%5Csqrt%7B64%7D%20%5C%5Cx%3D8)
Mel should use the least common multiple to solve the problem
<u>Solution:</u>
Given, Mel has to put the greatest number of bolts and nuts in each box so each box has the same number of bolts and the same number of nuts.
We have to find that should Mel use the greatest common factor or the least common multiple to solve the problem?
He should use least common multiple.
Let us see an example, suppose 12 bolts and nuts are to be fit in 6 boxes.
Then, if we took H.C.F of 12 and 6, it is 6, which means 6 bolts and nuts in each box, but, after filling 2 boxes with 6 bolts and nuts, there will be nothing left, which is wrong as remaining boxes are empty.
So the remaining method to choose is L.C.M.
Hence, he should use L.C.M method.
