All categories

2 years ago

Consider the quadratic equation 2x² + 72 + k = 0. Which value of k results in the equation having complex solutions?

Mathematics

1 answer:

postnew [5]2 years ago

5 0

Hi there!

$\large\boxed{k> 6.125}$

We can use discriminants to determine the value of k for which the equation would have complex solutions. (Those involving i)

If b² - 4ac < 0, then the equation will have complex solutions. Therefore:

Plug in the given values of b and a to solve:

7² - 4(2)(k) < 0

Simplify:

49 - 8k < 0

Solve the inequality:

49 < 8k

6.125 < k

k > 6.125. Anything greater than 6.125 would result in complex solutions.

You might be interested in

From the street, you drive down 6 levels in a parking garage. When you leave, you drive back up 6 levels. Which expression repre

oksian1 [2.3K]

Answer:

1.)

Step-by-step explanation:

When driving downwards, that is negative because you are subtracting. Then, when driving upwards, you are adding.

8 0

2 years ago

2 x 10 in standard form

lilavasa [31]

Answer:

y = 3 suh slid este ob cine este a, b și g au nevoie de acel kinfo pentru a termina

Step-by-step explanation:

bah de fort

3 0

3 years ago

I need help with this

Ulleksa [173]

No, tahts the answer

8 0

2 years ago

What is the equation of a line that contains the point (6,-4) and has a slope of 3/4?

elixir [45]

Answer:

B. y+ 4 = 3/4 (x-6)

Step-by-step explanation:

Given:

m = 3/4

Slope-intercept:

y - y1 = m(x - x1)

y + 4 = 3/4(x - 6)

3 0

2 years ago

(4^4)^5 the answer in simplest terms

Ipatiy [6.2K]

Answer:

2^40.

Step-by-step explanation:

(4^4)^5

= 4^(4*5)

= 4^20

= (2^2)^20

= 2^40.

4 0

2 years ago

Read 2 more answers

Consider the quadratic equation 2x² + 72 + k = 0. Which value of k results in the equation having complex solutions?​

Consider the quadratic equation 2x² + 72 + k = 0. Which value of k results in the equation having complex solutions?