The value of Mr Banks's property was $250,000
What percentage of the property is left for charity?
The percentage of property left for charity can be determined as the 100% of the property minus all percentages given to others
% left for charity=100%-50%-22%-16%
% left for charity=12.00%
12.00% of the property=$30,000
1.00% of the property =$30,000/12
1.00% of the property =$2,500
100.00% of the property=$2500*100
100.00% of the property=$250,000
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Answer:
Now we can calculate the p value with the following probability:
Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5
Step-by-step explanation:
Data given and notation
n=75 represent the random sample taken
estimated proportion of interest
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic
represent the p value
System of hypothesis
We want to verify if the true proportion is higher than 0.5:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info given we got:
Now we can calculate the p value with the following probability:
Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5
Answer:
when Y = 2, P(2) = 1/6 = 0.167
when Y = 3, P(3) = 2/6 = 0.333
when Y = 4, P(4) = 3/6 = 0.5
Step-by-step explanation:
Total number of possible ways to choose 2 components for defectives out of 4 components = 4C2 = 6
Y can only take values of 2, 3 and 4
So, Probability of Y = P(Y) = 1C(Y-1) / 6
when Y = 2, P(2) = 1/6 = 0.167
when Y = 3, P(3) = 2/6 = 0.333
when Y = 4, P(4) = 3/6 = 0.5
25 because 5 times 5 is 25 im writing more because it has to be at least 20 characters
