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3 years ago

5k + (-7) = 13 what does k =

Mathematics

2 answers:

Taya2010 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Here you go mate

PEMDAS

Parenthesis

Exponent

Multiplication

Division

Addition

Subtraction

Step 1

5k+(-7)=13 Equation/Question

Step 2

5k+(-7)=13 Remove parenthesis

5k=20

Step 3

5k=20 Divide 5 from the sides Check (5)(4)=20

answer

Scilla [17]3 years ago

5 0

Answer:

k = 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Step-by-step explanation:

Step 1: Define

5k + (-7) = 13

Step 2: Solve for k

Simplify equation: 5k - 7 = 13
Addition Property of Equality: 5k - 7 + 7 = 13 + 7
Simplify equation: 5k = 20
Division Property of Equality: 5k/5 = 20/5
Simplify equation: k = 4

Step 3: Check

Plug in k into the original equation to verify it's a solution.

Substitute in k: 5(4) + (-7) = 13
Multiply: 20 + (-7) = 13
Add: 13 = 13

Here we see that 13 does indeed equal 13.

∴ k = 4 is the solution to the equation.

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3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

4 years ago

Read 2 more answers

Is 5 a solution to 2x + 5 = 15? Yes or No How do you know?

dybincka [34]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I dont understand how to simplify an expression with exponents

Mashutka [201]

Answer:

3^4

Step-by-step explanation:

Simplifying an expression with expression with exponents:

If they are dividing, we keep the base and subtract the exponents. For example:

$\frac{a^x}{a^y}=a^{x-y}$

In this question:

$\frac{3^2}{3^{-2}}=3^{2-(-2)}=3^{2+2}=3^4$

8 0

1 year ago