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Verizon [17]
2 years ago
6

HELP ME PLSSSSSSS!!!!!!!!!

Mathematics
1 answer:
goblinko [34]2 years ago
4 0

Domain of the function

<h2 /><h2>[-3,5)</h2>
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What is the weight of a bowling ball with a 5 in. radius if we know that one cubic inch weighs 1/100th of a pound?
lorasvet [3.4K]
<h2>Greetings!</h2><h3>To find the total area of the bowling ball, which we presume is spherical, the equation is:</h3>

\frac{4}{3}πr³

<h3>So we know that the radius is 5, so we can substitute that into the equation:</h3>

\frac{4}{3} x π x 5³ = 523.599 or 524 to 1dp.

<h3>Seeing as this is 524 cubic inches, we can convert this into pounds by dividing this by 100, because one cubic inch weights \frac{1}{100} as stated.</h3>

524 ÷ 100 = 5.24lb

<h3>So your answer would be B, 5.24lb.</h3>
<h2>Hope this helps!</h2>

6 0
3 years ago
Will mark brainlyest
ArbitrLikvidat [17]

Answer: Angles 4 and 5

Step-by-step explanation:

Supplementary angles are angles that add up to 180. The only angle pairs the add up to 180 (you can tell by seeing if two angles are the only two on a straight line) are angles 4 and 5, and angles 3 and 4. Angles 3 and 4 isn’t an option, so it’s 4 and 5.

3 0
2 years ago
Read 2 more answers
BRAINLIEST <br> Please answer these
zheka24 [161]

3.14 is used for pi.

6.  r = \sqrt{\frac{A}{\pi } }

14.00

7. d = \frac{c}{\pi }

5.00

8. d = 2 \sqrt{\frac{A}{\pi } }

23.01

9. r = \frac{c}{2\pi }

20.01

10. d\pi = 2 \sqrt{{A}

31\pi

11. r\pi = \frac{c}{2}

22.5\pi

Hope this helps :)

6 0
3 years ago
Sara goes on a slingshot ride in an amusement park. she is strapped into a spherical ball that has a radius of centimeters. what
Kobotan [32]
I hope this helps you




volume of sphere =4/3.pi.r^3
6 0
3 years ago
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
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