Answer with explanation:
→→→Function 1
f(x)= - x²+ 8 x -15
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= - 2 x + 8
Put,f'(x)=0
-2 x+ 8=0
2 x=8
Dividing both sides by , 2, we get
x=4
Double differentiating the function
f"(x)= -2, which is negative.
Showing that function attains maximum at ,x=4.
Now,f(4)=-4²+ 8× 4-15
= -16 +32 -15
= -31 +32
=1
→→→Function 2:
f(x) = −x² + 2 x − 3
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= -2 x +2
Put,f'(x)=0
-2 x +2=0
2 x=2
Dividing both sides by , 2, we get
x=1
Double differentiating the function,gives
f"(x)= -2 ,which is negative.
Showing that function attains maximum at ,x=1.
f(1)= -1²+2 ×1 -3
= -1 +2 -3
= -4 +2
= -2
⇒⇒⇒Function 1 has the larger maximum.
5>x because you can subtract 5 from both sides and 3x from both sides
Answer:
3
Step-by-step explanation:
You want the greatest of three consecutive odd integers that have a sum of 3.
<h3>Average</h3>
The average of the integers is their sum divided by their number:
average = 3/3 = 1
This is the value of the middle of the three integers, so they are ...
-1, 1, 3
The greatest of the three is 3.
Answer:
8xh>168, and h>21.
Step-by-step explanation:
I took this quiz.
5/9. 5/6 times 2/3 and then simplifying is how I did this.
