A and C I’m pretty sure D is also equivalent to 5.
-5*3+2-7+3*6= -15+3-7+18= -1
Answer:
0.13 ft/min
Step-by-step explanation:
We are given that

We have to find the increasing rate of change of height of pile when the pile is 12 ft high.
Let d be the diameter of pile
Height of pile=h
d=h
Radius of pile,r=
Volume of pile=

h=12 ft
Substitute the values



Answer:
is there any more number because there should a more then one number
* can you write the other number because i can't do it without the number or you can just take the picture of the whole things.
Step-by-step explanation: