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xenn [34]
3 years ago
12

The box plot below represents some data set. What is the interquartile range (IQR) of

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

I think the IQR is 100

Step-by-step explanation:

You would have to find the first and third quartiles first. After that you would subtract the third quartile by the first to get the IQR

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Which table represents a nonlinear function?
elena-s [515]

Answer:

C

Step-by-step explanation:

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3 years ago
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Find an equation of the plane with the given characteristics. The plane passes through the points (4, 3, 1) and (4, 1, -7) and i
Minchanka [31]

Answer:

3x - 4y + z = 1

Step-by-step explanation:

Given

Point\ 1 = (4,3,1)

Point\ 2 = (4,1,-7)

Perpendicular to 8x + 7y + 4z = 18

Required

Determine the plane equation

The general equation of a plane is:

a(x-x_1) + b(y - y_1) + c(z-z_1) = 0

For n =

(x_1,y_1,z_1) = (4,3,1)

(x_2,y_2,z_2) = (4,1,-7)

First, we need to determine parallel vector V_1

V_1 =

V_1 =

V_1 =

V_1 is parallel to the required plane

From the question, the required plane is perpendicular to 8x + 7y + 4z = 18

Next, we determine vector V_2

V_2 =

This implies that the required plane is parallel to V_2

Hence: V_1 and V_2 are parallel.

So, we can calculate the cross product V_1 * V_2

V_1 =

V_2 =

n = V_1 * V_2

V_1 * V_2 =\left[\begin{array}{ccc}i&j&k\\0&2&8\\8&7&4\end{array}\right]

The product is always of the form + - +

So:

V_1 * V_2 = i\left[\begin{array}{cc}2&8\\7&4\end{array}\right]  -j\left[\begin{array}{cc}0&8\\8&4\end{array}\right] +k\left[\begin{array}{cc}0&2\\8&7\end{array}\right]

Calculate the product

V_1 * V_2 = i(2*4- 8*7) - j(0*4- 8*8) + k(0*7 - 2 * 8)

V_1 * V_2 = i(8- 56) - j(0- 64) + k(0 - 16)

V_1 * V_2 = i(-48) - j(- 64) + k(- 16)

V_1 * V_2 = -48i +64j - 16k

So, the resulting vector, n is:

n =

Recall that:

n =

By comparison:

a = -48   b = 64   c = -16

Substitute these values in a(x-x_1) + b(y - y_1) + c(z-z_1) = 0

-48(x-x_1) + 64(y - y_1) -16(z-z_1) =0

Recall that:(x_1,y_1,z_1) = (4,3,1)

So, we have:

-48(x-4) + 64(y - 3) -16(z-1) =0

-48x + 192 + 64y -192 - 16z +16 = 0

Collect Like Terms

-48x + 64y - 16z = 0 - 192 + 192 - 16

-48x + 64y - 16z = -16

Divide through by -16

3x - 4y + z = 1

<em>Hence, the equation of the plane is</em>3x - 4y + z = 1<em></em>

4 0
3 years ago
Write the equation. 5 more than a number times 2 is 2
suter [353]

(5 +n)\cdot2 = 2

3(2 -n) > 7

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3 years ago
What is the mode of 5,4,10,5,10,10,2,8,10,5?
miv72 [106K]
The Mode is 10 as it is the most repeated number.
3 0
3 years ago
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Solve for x: 3 − (2x − 5)&lt; −4(x + 2
guapka [62]

Answer:x<−8

Step-by-step explanation:

8 0
3 years ago
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