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2 years ago

The box plot below represents some data set. What is the interquartile range (IQR) of

Mathematics

1 answer:

vesna_86 [32]2 years ago

6 0

Answer:

I think the IQR is 100

Step-by-step explanation:

You would have to find the first and third quartiles first. After that you would subtract the third quartile by the first to get the IQR

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Plzzzzzzzzzzzzzzzzzzzzz answer!!!!!!!!!!!!!

GrogVix [38]

Answer:

This is quadratic trinomial

Step-by-step explanation:

It has x^2 (square) and consists of 3 parts

7 0

3 years ago

How do you find the solution of this proportion? 4/9 = m2-1/54 m2 is m to the power of 2

andrew11 [14]

Take the root of both sides and solve.

7 0

2 years ago

Please explain step by step

Alja [10]

Let's find the value of x

Since the sum of internal angles of a triangle is 180°

therefore,

$\hookrightarrow \: (2x - 2) \degree + (x + 5) \degree + 90 \degree = 180 \degree$

$\hookrightarrow \: 2x - 2 \degree + x + 5\degree = 180\degree - 90\degree$

$\hookrightarrow \: 3x + 3\degree = 90\degree$

$\hookrightarrow \: 3(x + 1) = 3(30)$

$\hookrightarrow \: x + 1\degree = 30\degree$

$\hookrightarrow \: x = 29\degree$

4 0

3 years ago

What value of t makes (-2) +(-11) = t a true sentence?

Bas_tet [7]

Answer:

t = -13

Step-by-step explanation:

Given expression:

(-2) +(-11) = t

Solving for t:

-13 = t
t = -13

8 0

3 years ago

Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π

lorasvet [3.4K]

The instantaneous rate of change of g with respect to x at x = π/3 is 1/2.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The instantaneous rate of change at a given value of $x$ can be found by concept of derivative, which is described below:

$g(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Where $h$ is the difference rate.

In this question we must find an expression for the instantaneous rate of change of $g$ if $f(x) = \sin x$ and evaluate the resulting expression for $x = \frac{\pi}{3}$ . Then, we have the following procedure below:

$g(x) = \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin h}{h}\cdot \lim_{h \to 0} \cos x$

$g(x) = \cos x$

Now we evaluate $g(x)$ for $x = \frac{\pi}{3}$ :

$g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}$

The instantaneous rate of change of g with respect to x at x = π/3 is 1/2. $\blacksquare$

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/11606037

4 0

2 years ago