Answer:
length : 8 m
width : 13/2 = 6.5 m
Step-by-step explanation:
area of rectangle = l(ength)×w(idth) = 52
l = 2w - 5
=> (2w - 5)×w = 52
=> 2w² -5w - 52 = 0
we know, when transforming this quadratic equation into a multiplication of two expressions of w, that we need to have 2w and w (to make 2w²), and then which 2 numbers multiply to 52 and add to -5 (when one is multiplied by 2 due to 2w) : -13 and 4
=> (2w - 13)×(w + 4) = 0
=> 2 solutions for w :
2w-13 = 0
2w = 13, w = 13/2
w+4 = 0, w = -4
negative values for a side length of a shape do not make sense, so the only usable solution is w = 13/2
=> l = 2w - 5 = 13 - 5 = 8
Answer:
it means when x =0
so 6*0+12y=60
12y=60
y=5
Step-by-step explanation:
Answer:
option 1
Step-by-step explanation:
formula:(x-h)^(2)*(y-k)^(2)=r^2
well if you move the circle 3 units left h is (-3), plug it in, you get 3, so it is (x+3)^2*(y-k)^(2)=r^2
if you move the circle 2 units up, plug it in you get (-2), so it is
(x+3)^2*(y-2)^(2)=r^2
now, the radius is 3 (we can see from the graph) so radius ^2 is 9, thus
(x+3)^2*(y-2)^(2)=9
this is the answer, and the option that has it is answer is option 1
After solving ![\sqrt[5]{128x^8y^2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B128x%5E8y%5E2%7D)
we get ![2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}](https://tex.z-dn.net/?f=2x%5Csqrt%5B5%5D%7B4%7D%5Csqrt%5B5%5D%7Bx%5E3%7D%5Csqrt%5B5%5D%7By%5E2%7D)
Step-by-step explanation:
We need to solve
Applying the rule: ![\sqrt[a]{xy}=\sqrt[a]{x}.\sqrt[a]{y}](https://tex.z-dn.net/?f=%5Csqrt%5Ba%5D%7Bxy%7D%3D%5Csqrt%5Ba%5D%7Bx%7D.%5Csqrt%5Ba%5D%7By%7D)
![\sqrt[5]{128x^8y^2}\\=\sqrt[5]{128}\sqrt[5]{x^8}\sqrt[5]{y^2}\\We\,\,know\,\,that\,\,128=2\times2\times2\times2\times2\times2\times2=2^7\,\,or\,\,2^5.2^2\\=\sqrt[5]{2^5.2^2}\sqrt[5]{x^5.x^3}\sqrt[5]{y^2}\\=(2^5)^{\frac{1}{5}}\sqrt[5]{2^2}\sqrt[5]{x^5}\sqrt[5]{x^3}\sqrt[5]{y^2}\\=2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B128x%5E8y%5E2%7D%5C%5C%3D%5Csqrt%5B5%5D%7B128%7D%5Csqrt%5B5%5D%7Bx%5E8%7D%5Csqrt%5B5%5D%7By%5E2%7D%5C%5CWe%5C%2C%5C%2Cknow%5C%2C%5C%2Cthat%5C%2C%5C%2C128%3D2%5Ctimes2%5Ctimes2%5Ctimes2%5Ctimes2%5Ctimes2%5Ctimes2%3D2%5E7%5C%2C%5C%2Cor%5C%2C%5C%2C2%5E5.2%5E2%5C%5C%3D%5Csqrt%5B5%5D%7B2%5E5.2%5E2%7D%5Csqrt%5B5%5D%7Bx%5E5.x%5E3%7D%5Csqrt%5B5%5D%7By%5E2%7D%5C%5C%3D%282%5E5%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%5Csqrt%5B5%5D%7B2%5E2%7D%5Csqrt%5B5%5D%7Bx%5E5%7D%5Csqrt%5B5%5D%7Bx%5E3%7D%5Csqrt%5B5%5D%7By%5E2%7D%5C%5C%3D2x%5Csqrt%5B5%5D%7B4%7D%5Csqrt%5B5%5D%7Bx%5E3%7D%5Csqrt%5B5%5D%7By%5E2%7D)
So, After solving we get
Keywords: Solving with Exponents
Learn more about Solving with Exponents at:
#learnwithBrainly
