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RoseWind [281]
2 years ago
11

Find the quotient 3^15/3^3

Mathematics
1 answer:
Sati [7]2 years ago
6 0

There is a property called "Quotient of powers property", which states that:

\frac{a^m}{a^n}=a^{(m-n)}

Where "a" is the common base and "m" and "n" are exponents.

For this case, you have:

\frac{3^{(15)}}{3^3}

Then, in order to find the quotient, you must apply the Quotient of powers property. You need to write the common base (in this case is 3) and then subtract the exponents.

So, you get that the quotient is:

\frac{3^{(15)}}{3^3}=3^{(15-3)}=3^{(12)}

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Which expression represents exponential decay
Lelu [443]

Given:

The exponential equations in the options.

To find:

The equation which represents exponential decay.

Solution:

The general exponential equation is

y=ab^x

where, a is initial value and b is growth rate.

If b<1, then it is an equation of exponential decay.

If b>1, then it is an equation of exponential growth.

In option A, b=31>1, i.e., exponential growth.

In option B, b=3.1>1, i.e., exponential growth.

In option C, b=0.13<1, i.e., exponential decay.

In option D, b=1.03>1, i.e., exponential growth.

Only y=10(0.13)^x represents exponential decay.

Therefore, the correct option is C.

5 0
3 years ago
Find the product of monomials<br> 3a^4b^-2 and 2a^7b^-1
Inga [223]
(3a^4 * b^-2) * (2a^7 * b^-1)
= 6*a^(4+7)*b^(-2-1)
= 6*a^11*b^-3
5 0
3 years ago
Which national legislature has themost members?
AfilCa [17]
China has the most members.
8 0
3 years ago
Which point is located on quadrant IV
pychu [463]

It's the letter D hope it helps

8 0
3 years ago
3.) SOLVE FOR X.
gayaneshka [121]

The value of x in the secants intersection is 1 units

The value of NM in the tangent and secant intersection is 51 units

<h3>How to find length when secant and tangent intersect?</h3>

The first question, two secant intersect outside the circle.

Therefore,

(6x + 8x)8x = (9 + 7)7

14x(8x) = 16(7)

112x² = 112

x² = 112 / 112

x = √1

x = 1

The second question, tangent and secant intersect,

Therefore,

(x + 3)² = (x - 3)(16 + x - 3)

(x + 3)² = (x - 3)(x + 13)

(x + 3)(x + 3) = (x - 3)(x + 13)

x² + 3x + 3x + 9 = x² + 13x - 3x - 39

x² + 9x + 9 = x² + 10x - 39

x² - x² + 9x - 10x = -39 - 9

-x = - 48

x = 48

NM = 48 + 3 = 51 units

learn more on secant and tangent here: brainly.com/question/12477905

#SPJ1

6 0
2 years ago
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