Question

1) If two dice are rolled simultaneously, find the probability of the following events.

Answer 1

[i] 1/6.

[ii] 0.

Justification:

Possible outcomes :-

(1,1);(1,2);(1,3);(1,4);(1,5);(1,6)

(2,1);(2,2);(2,3);(2,4);(2,5);(2,6)

(3,1);(3,2);(3,3);(3,4);(3,5);(3,6)

(4,1);(4,2);(4,3);(4,4);(4,5);(4,6)

(5,1);(5,2);(5,3);(5,4);(5,5);(5,6)

(6,1);(6,2);(6,3);(6,4);(6,5);(6,6)

Total possible outcomes = 6 × 6 = 36.

[i] Favourable event = (4,6);(5,5);(5,6);(6,4);(6,5);(6,6) = 6.

P(A) = 6/36 = 1/6.

[ii] Favourable event = 0.

P(B) = 0/36 = 0.

Answer 2

Answer:

$\huge\fbox\red{A}\fbox\pink{n}\fbox\purple{s}\fbox\green{w}\fbox\blue{e}\fbox\orange{r}$

$1. \frac{1}{6}$

$2.0$