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alexandr1967 [171]
3 years ago
8

Three roads, A, B and C, all run south to north. They each meet a highway that runs west to east. Road B is 4.6 mi east of Road

A Road C is 3.1 mi west of Road B.
Describe the location of Road C with respect to Road A?
Mathematics
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

Road C is 1.5 mi east of Road A

Step-by-step explanation:

we know that

Road B is 4.6 mi east of Road A

Road C is 3.1 mi west of Road B

so

Road C is between Road A and Road B

AB=4.6 miles

CB=3.1 miles

AB=AC+CB

Solve for AC

AC=AB-CB

AC=4.6-3.1=1.5 miles

therefore

Road C is 1.5 mi east of Road A

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Sonja [21]

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Add:

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3 years ago
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Answer:

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Step-by-step explanation:

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\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

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To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

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x = 0 or x = \pi.

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