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alexandr1967 [171]
3 years ago
8

Three roads, A, B and C, all run south to north. They each meet a highway that runs west to east. Road B is 4.6 mi east of Road

A Road C is 3.1 mi west of Road B.
Describe the location of Road C with respect to Road A?
Mathematics
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

Road C is 1.5 mi east of Road A

Step-by-step explanation:

we know that

Road B is 4.6 mi east of Road A

Road C is 3.1 mi west of Road B

so

Road C is between Road A and Road B

AB=4.6 miles

CB=3.1 miles

AB=AC+CB

Solve for AC

AC=AB-CB

AC=4.6-3.1=1.5 miles

therefore

Road C is 1.5 mi east of Road A

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117.39

Step-by-step explanation:

The other number is a negative and the opposing is a positive

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The question for the graph has a leading coefficient that is___. What are the possible degrees for the equation of this graph
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Step-by-step explanation:

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What is the instantaneous acceleration of the particle at point B?
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3 years ago
Find the Maclaurin polynomials of orders n = 0, 1, 2, 3, and 4, and then find the nth Maclaurin polynomials for the function in
Zielflug [23.3K]

Answer:

Σ(-1)^kx^k for k = 0 to n

Step-by-step explanation:

The nth Maclaurin polynomials for f to be

Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......

The given function is.

f(x) = 1/(1+x)

Differentiate four times with respect to x

f(x) = 1/(1+x)

f'(x) = -1/(1+x)²

f''(x) = 2/(1+x)³

f'''(x) = -6/(1+x)⁴

f''''(x) = 24/(1+x)^5

To calculate with a coefficient of 1

f(0) = 1

f'(0) = -1

f''(0) = 2

f'''(0) = -6

f''''(0) = 24

Findinf Pn(x) for n = 0 to 4.

Po(x) = 1

P1(x) = 1 - x

P2(x) = 1 - x + x²

P3(x) = 1 - x+ x² - x³

P4(x) = 1 - x+ x² - x³+ x⁴

Hence, the nth Maclaurin polynomials is

1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n

= Σ(-1)^kx^k for k = 0 to n

6 0
3 years ago
3q+4+9=-14 <br> what is Q
BlackZzzverrR [31]

Hi! Your answer is q = -9

Please see an explanation for a better and clear understanding to your problem.

Any questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

Since we want to solve for q-term. That means we are going to isolate q-term.

\huge{3q+4+9=-14}

We can add 4 and 9 together.

\huge{3q+13=-14}

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

\huge{3q+13-13=-14-13}\\\huge{3q=-27}

We are reaching to the final step where we divide the whole equation by 3.

\huge{\frac{3q}{3}=-\frac{27}{3}}\\\huge{q=-9}

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!

To check the answer, simply substitute q = -9 in the equation.

\huge{3q+4+9=-14}\\\huge{3(-9)+13=-14}\\\huge{-27+13=-14}\\\huge{-14=-14}

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.

Hope this helps!

5 0
3 years ago
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