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saveliy_v [14]
3 years ago
5

An astronaut rides in a circular training accelerator at 16 m/s. If the radius of the accelerator is 8.0 meters, what is his cen

tripetal acceleration? m/s2 Enter the answer Submit Answer I don't know this mprove this question​
Physics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

a=32\ m/s^2

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2

So, the required centripetal acceleration is 32\ m/s^2.

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In a tug of war, two teams exerts a force of 30 N each. What is the net force acting on the rope?
Arte-miy333 [17]

The force exerted by each team is 30 N. The forces are in the direction opposite to each other.

Force exerted by team 1, F_{1}=30 N

Force exerted by team 2,F_{2}=-30 N

Net force, F=F_{1} +F_{2}

=30+(-30)=0

Therefore, net force on the rope is 0 N.

4 0
3 years ago
Across what potential difference does an electron have to be accelerated in order to reach the speed v=3e7 m/s?
zmey [24]

When an electron is accelerated through potential difference then the speed that it attain will be explained by energy conservation

here by energy conservation we can say that

change in kinetic energy of electron = electrostatic potential energy gained through given potential difference

kinetic energy is given as

KE = \frac{1}{2}mv^2

electrostatic potential energy is given as

PE = qV

now by energy conservation

qV = \frac{1}{2}mv^2

given that for electron

m = 9.1 * 10^{-31} kg

v = 3 * 10^7 m/s

q = 1.6 * 10^{-19} C

now by plug in values

1.6 * 10^{-19} * V = \frac{1}{2}*9.1* 10^{-31} *(3*10^7)^2

V = \frac{4.095 * 10^{-16}}{1.6 * 10^{-19}}

V = 2559.4 Volts

So here it is accelerated through potential difference of 2559.4 Volts

4 0
3 years ago
Let’s say you have a cart of some mass and when pushed with 10N of force, the cart accelerates at 5.0 m/s/s. If you were to push
Korolek [52]

Answer:

a. The acceleration would increase.

Explanation:

because we know that

F=ma

m= mass and a= acceleration

so Mass is same for the cart in any situation that's why only acceleration could increase.

7 0
3 years ago
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Two asteroids with masses 3.45 x 103 kg and 6.06 x 104 kg are separated by
alexgriva [62]

Answer:

B

Explanation

ap3x

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What is the proper equation to use for finding the net force in the y direction
mart [117]

The direction of the acceleration is the same as the direction of the net force: 34 degrees. Apply the equation <eq04017> to find the magnitude of the net force, giving you 35.4 N. Use the magnitude of the force and the mass to find the magnitude of the acceleration: a = F/m = (35.4 N)/(0.10 kg) = 354 m/s2.

8 0
3 years ago
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