He blocked his man using a force of 23 N moving him backward 2 meters ,how much work did he do?

Physics

1 answer:

Paul [167]4 years ago

6 0

Answer:

work done = force x distance

Explanation:

F = 23 N

D = 2m

W = 23 * 2 = 46 J

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Three identical springs, each with stiffness 1200 N/m are attached in series (that is, end to end) to make a longer spring to ho

OLga [1]

<h2>Answer:</h2>

400N/m

<h2>Explanation:</h2>

When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e

$\frac{1}{m}$ = ∑ⁿ₁ [ $\frac{1}{k_{i}}$ ] -----------------------(i)

That is;

$\frac{1}{m}$ = $\frac{1}{k_{1}}$ + $\frac{1}{k_{2}}$ + $\frac{1}{k_{3}}$ + . . . + $\frac{1}{k_{n}}$ -------------------(ii)

If they have the same value of stiffness say s, then equation (ii) becomes;

$\frac{1}{m}$ = n x $\frac{1}{s}$ -----------------(iii)

Where;

n = number of springs

From the question,

There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;

n = 3

s = 1200N/m

Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;

$\frac{1}{m}$ = 3 x $\frac{1}{1200}$