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Oduvanchick [21]
4 years ago
15

He blocked his man using a force of 23 N moving him backward 2 meters ,how much work did he do?

Physics
1 answer:
Paul [167]4 years ago
6 0

Answer:

work done = force x distance

Explanation:

F = 23 N

D = 2m

W = 23 * 2 = 46 J

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<h2>Answer:</h2>

400N/m

<h2>Explanation:</h2>

When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e

\frac{1}{m} = ∑ⁿ₁ [\frac{1}{k_{i}}]          -----------------------(i)

That is;

\frac{1}{m} = \frac{1}{k_{1}} + \frac{1}{k_{2}} + \frac{1}{k_{3}} + . . . + \frac{1}{k_{n}}      -------------------(ii)

If they have the same value of stiffness say s, then equation (ii) becomes;

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Where;

n = number of springs

From the question,

There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;

n = 3

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Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;

\frac{1}{m} = 3 x \frac{1}{1200}

\frac{1}{m} = \frac{3}{1200}

\frac{1}{m} = \frac{1}{400}

Cross multiply;

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Therefore, the stiffness of the longer spring is 400N/m

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