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Mademuasel [1]
3 years ago
9

It takes one week for a crew of workers to pave 3/5 kilometer of a road. At that rate, how long will it take to pave 1 kilometer

?
Mathematics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

1.67 weeks

Step-by-step explanation:

Let X= time it will take to pave 1 kilometer?

1 week=3/5 kilometer

X week =1 kilometer

Cross multiply

3/5 X= 1

3X= 5

X= 5/3

1.67 weeks

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Answer:

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Step-by-step explanation:

Set up an equation where q is the unknown number:

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Solve for q by subtracting 11 from both sides:

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Joseph pays $20 for his base phone plan in addition to the $0.23 per text. Micki pays $10 for her phne plan plus $0.15 per text.
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Not really Specific in asking in what way you want it answered... So here is what Im able to understand.


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Step-by-step explanation:

Hope it helps you

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100 POINTS If x and y are real numbers, what is the simplified radical form of <img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%
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Please help me i don't know what to do <br> please show your work
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<h3>Distributive Property</h3>

The distributive property lets you group or ungroup terms using parentheses. It lets you multiply an external factor by every term in parentheses, expressing the result as a sum:

... a(b + c) = ab + ac . . . . . . factor <em>a</em> multiplies the terms <em>b</em> and <em>c</em>

and it lets you remove a common factor from different terms, putting that factor outside parentheses:

... ab + ac = a(b + c)

The letters <em>a</em>, <em>b</em>, <em>c</em> here can stand for any number or expression.

<h3>Homework</h3>

20. To do this problem, you need to eliminate the parentheses using the distributive property. Then, "collect terms," which is another application of the distributive property. The external factor outside the parentheses is (-2/3). Multiply that by each term in parentheses, and add the results.

After that, recognize that c is a factor of two of the terms. Add their coefficients to simplify that sum to one term.

-\dfrac{2}{3}(12c-9)+14c=\left(-\dfrac{2}{3}\right)(12c)+\left(-\dfrac{2}{3}\right)(-9)+14c=-8c+6+14c\\\\=c(-8+14)+6\\\\=6c+6

22. You are to evaluate the expression with x=2 two ways: as is, and after you simplify it by combining like terms.

<u>As is:</u>

-8x+5-2x-4+5x\\=-8(2)+5-2(2)-4+5(2)\\=-16+5-4-4+10\\=-9

<u>Simplified:</u>

-8x+5-2x-4+5x\\=x(-8-2+5)+(5-4)=-5x+1\\=-5(2)+1=-10+1\\=-9

I prefer simplifying the expression first. The number of calculations and chances for error are reduced.

23. It is convenient to check for equivalence after simplifying both expressions.

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<u>Second Expression:</u>

7x^2+7y +4x^2-4y=(7+4)x^2+(7-4)y=11x^2+3y

The simplified forms of the expressions are identical, so we conclude the expressions are equivalent.

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