According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
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Answer:
x=90
y=67
Step-by-step explanation:
as the line that bisects the vertical angle of isosceles triangle perpendicularly bisects the base
so x=90
and sum of all sides of triangle is 180 so
90+23+y=180
therefore,y=67
We know it begins at 100. If we use a*b^t, then 100 is our a. 100*b^t. We can now divide 480 by 100. This is 4.8. 4.8 is b. f(t) = 100(4.8)^t
Answer:
y= -3x + 7
Step-by-step explanation:
y intercept= 7
slope= -3