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koban [17]
2 years ago
14

Simplify completely quantity 8 x minus 16 over quantity x squared minus 13 x plus 22 and find the restrictions on the variable.

Mathematics
1 answer:
Nostrana [21]2 years ago
5 0

Answer:

hope this helps !

Step-by-step explanation:

1) ( 8 x- 16 ) / (x²- 13 x + 22 ) = ( 8 x- 16 ) ( x - 11) ( x -2 ) = 8 ( x-2) ( x-11) ( x- 2 ) = 8/(x-11)

Restriction x ≠ 11 & x ≠ 2

since both values render the denominator = to 0 & we can't divide by 0.

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Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
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Kamila [148]

Answer:

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Step-by-step explanation:

3 0
2 years ago
What the answer fast
Alisiya [41]

Answer:

72

Step-by-step explanation:

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5 0
3 years ago
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