There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
<h3><u>
Solution:</u></h3>
Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Answer:175.84 ft
Step-by-step explanation: the equation would be diameter times pi
Answer:
c
Step-by-step explanation:
Since the figures are similar then the ratios of corresponding sides are equal, that is
= 
, substitute values
= 
( cross- multiply )
10YZ = 230 ( divide both sides by 10 )
YZ = 23 → c
You get imaginary roots for this equation.
x=4-5i
x=4+5i
63% decrease.
0.63•80=50.4kg
80kg-50.4kg=29.6kg
