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valentinak56 [21]
2 years ago
7

Solve: (4 × 6) ÷ (2 + 4) ÷ (8 ÷ 4) =

Mathematics
1 answer:
Bingel [31]2 years ago
8 0

Answer:

2

Step-by-step explanation:

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Y = -11x - 25 ...........(i)<br> y = 5x - 7 ...............(ii)
valkas [14]

Answer:

3/2

Step-by-step explanation:

5x-7=-11x-25

5x+11x=-25+7

16x=18

x=18/16

x=3/2

6 0
3 years ago
If 50 × a = 50, then what is the value of 50 − a ?
Paraphin [41]

Answer: 50 - a = 49

Step-by-step explanation:

50 x a =50

50 x 1 = 50

a=1

50 - a = 50 - 1

50 - 1 = 49

5 0
2 years ago
Read 2 more answers
What is the point of intersection when the system of equations below is graphed on the coordinate plane?
olya-2409 [2.1K]

Answer:

I.M.S. infinite many solutions

Step-by-step explanation:

this will come out to be the same line.

6 0
2 years ago
7) 43 is 31% of what number?<br>8) 105 is 42% of what number?​
Anna71 [15]

Answer:

7.) 138.71

8.) 250

Step-by-step explanation:

Was this the answer you were looking for?

5 0
3 years ago
Read 2 more answers
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
Paha777 [63]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

We know that,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

Using the trigonometric ratios, we get

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Hence, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

6 0
3 years ago
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