Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Answer:
4.5
Step-by-step explanation:
1±4±2±8±4±8=27
27÷6=4.5
Answer:
S₃ = 37
Step-by-step explanation:
given a₁ = 16 and r = 
, then
a₂ = a₁ × = 16 × = 12
a₃ = a₂ × = 12 × = 9
then
S₃ = a₁ + a₂ + a₃ = 16 + 12 + 9 = 37
If angle TSV=6x+17 then arc it intercept (SV)would be double it
6x+17=1/2 (15x+13)
12x+34=15x+13
21=3x
x=7
Arc SV=15(7)+13
=118
And angle TSV=6(7)+17
=59
There are 360 degrees in a circle and the measure of the arc would be equal to the central point so the sum of all the arcs equals 360
Arc SV+ arc SUV=360
118+SUV=360
Arc SUV=242
Answer:
whats the other angle
Step-by-step explanation:
