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Genrish500 [490]

3 years ago

7

Q3: The number of teachers in a school is increased from 45 to 55, express the number of increase in a ratio?

1 answer:

dalvyx [7]3 years ago

3 0

Answer:

increased from 45 to 55, express the number of increase in a ratio?

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Anyone 100% know dis answer

siniylev [52]

Answer:

Rotational symmetry

Step-by-step explanation:

The rectangle rotated 180 degrees to get the transformed rectangle.

4 0

3 years ago

A rectangular garden of area 456 square feet is to be surrounded on three sides by a brick wall costing $ 12 per foot and on one

solniwko [45]

Answer:

$l=2\sqrt{114}feet$ $b=2\sqrt{114}feet$ $\left ( l,b \right )=(21.3541,21.3541)$

Step-by-step explanation:

Given,

Area of garden=456 square feet

Brick wall cost three sides $=\$ 12$ per foot

fencing cost of one side $=\$ 7$ per foot

Let length and breadth of rectangular field is (l,b) feet

For minimizing the cost of material perimeter of garden should be minimum and area of garden is more.

Perimeter of garden $=2\left ( l+b \right )=k$

$l+b=k/2$

$l=k/2-b$

A= $l\times b=456$

A= $\left ( k/2-b \right )b=456$

Differentiating the equation to find maximum area

$\frac{d}{db}(\left ( k/2-b \right )b)=\frac{\partial 456}{\partial b}$

$k/2-2b=0$

$k=4b$

$l=4b/2-b$

$l=b$

To find $maxima$ again differentiating

$\frac{\partial A^2 }{\partial b^2}=\frac{\partial \left ( k/2-2b \right )}{\partial b}$

$\frac{\partial A^2 }{\partial b^2}$

The area is maximum when l=b

and perimeter is minimum

$l\times b=456$

$b^{2}=456$

$b=2\sqrt{114}feet$

$l=2\sqrt{114}feet$

Cost material

$=2\sqrt{114}\times 3\times 12+2\sqrt{114}\times 7$

$=72\sqrt{114}+14\sqrt{114}$

$=\$ 86\sqrt{114}$

$=\$ 918.22873$

Dimension of rectangular garden

$\left ( l,b \right )=(21.3541,21.3541)$

4 0

3 years ago

Elise is doing her homework. she plans to spend 1/2 hour on math homework and 1/4 hour on spelling words. which number is a comm

Reil [10]

I am pretty sure the answer you are looking for is 12

7 0

3 years ago

you are a school photographer taking individual and class pictures for 2 classes of 21 students each on average each individual

uysha [10]

Answer: Approximately 146 minutes (or if you need the simplified version the answer is 2 hours and 26 minutes). Step-by-step explanation: Step 1. Two classes of 21 students. To calculate that you would multiply 21 by 2. 21*2=42 Step 2. So now we know you need 42 individual pictures. If they each take 3 minutes to take you need to multiply 42 by 3. 42*3=126. So now you know it’ll take 126 minutes to take all the individual pictures. Step 3. Now, there are 2 classes of people and it takes 10 minutes to take each class picture. So do calculate that you need to multiply 10 by 2. 10*2=20. So it’ll take 20 minutes to take both class pictures. Step 4. Now we know it’ll take 126 minutes to take all the individual photos and 20 minutes to take the class photos. Now to calculate the total amount of time it’ll take to take all the photos you need to add 20 to 126. 126+20=146. So, it’ll take 146 minutes to take all the photos. Step 5. (You can skip this step if no simplification is needed in your problem) So, we all know there is 60 minutes in an hour so we’ll divide 146 by 60. 146/60=2.43. So, now we know it’ll take 2.43 hours to take all the photos. 2.43 hours is 2 hours and 26 minutes. I hope this helps!

4 0

3 years ago

Charlie makes $34 an hour and will get a 20% raise starting next week. Choose True or False for each statement.

Soloha48 [4]

Answer:

false

Step-by-step explanation:

it false

7 0

3 years ago