Answer:
corrcect
Step-by-step explanation:
Base times Hight
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
ANSWER
The height of the larger cone is 3cm
EXPLANATION
Since the two cones are similar we can use the scale factor to determine the height of the larger cone.
It was given that, the volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³.
The scale factor for the volume is

The scale factor for the length is
![k = \sqrt[3]{ \frac{27}{8} }](https://tex.z-dn.net/?f=k%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B27%7D%7B8%7D%20%7D%20)

To find the height of the larger cone, we multiply by
$4 dollars. My process was first, creating the matrix.
17= 2p + 3a p represents peaches and a for apricot
22= 4p + 2a
Answer:
131.88 centimeters
Step-by-step explanation:
diameter = radius*2
radius = 21
circumference =2*π*r
2*3.14*21= 131.88 centimeters