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enot [183]
3 years ago
5

The interarrival time of nuclear particles in a Monte Carlo simulation of a reaction is designed to have a uniform distribution

over an interval from 0 to 0.5 milliseconds. Determine the probability that the interarrival time between two particles will be:
Mathematics
1 answer:
jekas [21]3 years ago
7 0

Answer:

Incomplete question, but you can use the formulas given to solve it.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

Uniform distribution over an interval from 0 to 0.5 milliseconds

This means that a = 0, b = 0.5

Determine the probability that the interarrival time between two particles will be:

Considering a = 0, b = 0.5, and the question asked, you choose one of the three formulas above.

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Penny reads 11 pages in 1/3 hour. How many pages does she read per hour?
dolphi86 [110]

Answer:

33 pages per hour

Step-by-step explanation:

11 pages=1/3 hour

22 pages=2/3 hour

33 pages= 3/3 hour or 1 hour

5 0
3 years ago
Phonics is an instructional method in which children are taught to connect sounds with letters or groups of letters. A sample of
Fantom [35]

Answer:

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{23.44}{\sqrt{141}}

M = 3.25

The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.

The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

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3 years ago
20 POINTS AND BRAINIEST FOR THOSE WHO ANSWER CORRECTLY
Licemer1 [7]

Answer:

x^2 y ^4  ∛  [x^2  y ^2 ]   is the answer that I got

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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sergeinik [125]
f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\&#10;\hbox{statement 1 is false} \\ \\&#10;f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\&#10;f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8&#10;\\ f(-2)=f(2) \\&#10;\hbox{statement 2 is true}

f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\&#10;f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\&#10;71+8 \not= 143 \\&#10;f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\&#10;f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\&#10;71 \times 8 \not= 296 \\&#10;f(5) \times f(2) \not= f(10) \\&#10;\hbox{statement 4 is false}

Stamement 2. f(-2)=f(2) is true.
3 0
3 years ago
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

I=sen(t)-t.cos(t)+C

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

cos(t)=\sqrt{1-sen^2(t)}

Entonces:

cos(t)=\sqrt{1-x^2}

Devolviendo los cambios:

I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C

Es la respuesta correcta

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3 years ago
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