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Oksanka [162]
2 years ago
6

20 POINTS AND BRAINIEST FOR THOSE WHO ANSWER CORRECTLY

Mathematics
2 answers:
Licemer1 [7]2 years ago
8 0

Answer:

x^2 y ^4  ∛  [x^2  y ^2 ]   is the answer that I got

Step-by-step explanation:

Ludmilka [50]2 years ago
8 0

Answer:

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Step-by-step explanation:

(x^{4}y^{7})^{\frac{3}{4}}

Answer 1:

= x^{3}y^{5} \sqrt[4]{y}

Answer 2:

x^{3}y^{\frac{21}{4}}

Answer 3:

\sqrt[4](x^{4}y^{7})^{3}

I didn't know which one was correct, so I included all of them. I hope this helps!

You might be interested in
In Triangle A B C, what is the value of x? Triangle A B C. Angle A is (10 x minus 10) degrees, angle B is (8 x) degrees, angle C
svp [43]

Answer:

6.5

Step-by-step explanation:

The sum of all angles in a triangle are 180 degrees.

=> 10x -10 + 8x + 10x + 8 = 180

=> 28x -2 = 180

=> 28x = 182

=> x = 6.5

So, Angle A = 10 x 6.5 -10 = 65 - 10 = 55 degrees

     Angle B = 8 x 6.5 = 52 degrees

     Angle C = 10 x 6.5 + 8 = 65 + 8 = 73 degrees.

55 + 52 + 73 = 55 + 125 = 180 degrees

6 0
3 years ago
Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
PLEASE HELP ILY IF YOU DO
agasfer [191]

Answer:

who the holy christmas is ily

Step-by-step explanation:

maybe you call your dog that

wait do you have a dog?

anyways

thanks for the points

3 0
2 years ago
PLZS HELP NEED BY TODAY!!
Alex73 [517]
X=20. Because that line is 180 and u subtract 40 and u do 140/7= 20
3 0
2 years ago
Read 2 more answers
7. Sam lives exactly halfway between his friends, Danny and Leo. Danny's house is
geniusboy [140]

The point that Sam's house is located is at (2.5, -2)

<h3 /><h3>Midpoint of coordinate points</h3>

The formula for calculating the midpoint of coordinate is expressed as:

M(x, y) = {(x₁+x₂)/2, (y₁+y₂)/2}

Given the coordinate between their locations at (-4, 4) and (-9, 8)

Determine the midpoint

x = (-4+9)/2

x =5/2 = 2.5

Similarly

y = 4-8/2

y = -4/2

y = -2

Hence the point that Sam's house is located is at (2.5, -2)

Learn more on midpoint here: brainly.com/question/5566419
#SPJ1

6 0
1 year ago
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