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scZoUnD [109]
3 years ago
7

PLEASE HELP PLEASE EMERGENCY

Mathematics
2 answers:
joja [24]3 years ago
3 0
1, 5, 4, 2, 3 in that order
muminat3 years ago
3 0

Answer:First one is first step. 2 is Last step. 3 is fourth step. 4 is second step. 5 is Third step

Step-by-step explanation:

I went down the column

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What is the diameter of a circle with area of 113.04 square cm. use 3.14?<br><br><br> pls fast
galina1969 [7]

Answer:

diameter of a circle = 12cm

Step-by-step explanation:

Area of a circle = πr²

113.04 cm² = πr²

First, search for radius (r) :-

r = √(113.04/π)

r = 6 cm

As diameter is equals to 2×radius

The diameter of a circle = 2 × 6cm

Final answer = 12 cm

3 0
3 years ago
Read 2 more answers
Felix and Megan are going hiking and are trying to figure out how much water
andreev551 [17]

Answer:

w

Step-by-step explanation:

The amount of water they need to bring depends on how long they will be hiking.

4 0
1 year ago
PLEASE HELP. graph the set of points which model is most appropriate for the set (-6,4)(-4,0)(-3,-2)(-1,-7)
SOVA2 [1]
A linear equation would be the best fit, but the last point (-1,-7) kinda messes it up. If the -7 would have been a -6 the line y=-2x-8 would fit perfectly.
7 0
3 years ago
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
2 years ago
a square is put together by two triangles. the hypotenuse is 11 cm and width if 8 cm. find the height of the triangle.
maksim [4K]

Answer:

b ≈ 7.54 cm

Step-by-step explanation:

Pythagorean Theorem

a² + b² = c²

a and b are the sides and c is the hypotenuse

hypotenuse is 11 cm

a side is 8 cm

so

8² + b² = 11²

64 + b² = 121

-64           -64

       b² =  57

    √b² =  √57

       b ≈ 7.54 cm ( use ≈ because its rounded so its not exact)

3 0
4 years ago
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