How would you determine whether time series regression or exponential smoothing is better?

A Ferris wheel rotates 9π/8 radians prior to making a stop. The total height of the Ferris wheel is 246 ft. How far around did t

WARRIOR [948]

Answer:

The ferris wheel travelled 434.717 ft.

Step-by-step explanation:

Assuming that the ferris wheel is a perfect circle, then it's height is the same as the diameter of the circle, therefore it's radius is:

radius = height/2 = 246/2 = 123 ft

The distance travelled by the ferris wheel is the same as the length of the arc created by a angle of (9pi/8). The length of an arc is given by:

length = r*(angle in radians)

length = 123*(9pi/8)

length = 434.717 ft

The ferris wheel travelled 434.717 ft.

5 0

2 years ago

Find the length of the diagonal of a square with perimeter 32.

snow_lady [41]

Answer:

i think A. because she is 4/2

7 0

2 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago

Escribe 18 en palabras tal y como la escribirías en tu cheque

Semmy [17]

Answer:

Diez y ocho y 00/100.

4 0

2 years ago

Read 2 more answers

Please help on number 3

lisov135 [29]

The answer is 17/36. (Fraction)

5 0

3 years ago