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3 years ago

Please help, been stuck on this for a while.

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

5 0

Answer:its blurry

Step-by-step explanation:

cant see it

34kurt3 years ago

3 0

Answer:

x = 34.6

Step-by-step explanation:

$x\:=\:\frac{\left(20\cdot \:sin\left(60\right)\right)}{sin\left(30\right)}$

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3 years ago

The cost of a company picnic varies directly as the number of employees attending the picnic. If a company picnic costs $487.50

Drupady [299]

The company picnic cost $ 1300 for 80 employees

Solution:

Given that cost of a company picnic varies directly as the number of employees attending the picnic

Let "c" be the company picnic cost

Let "n" be the number of employees attending the picnic

Therefore,

$cost \propto \text{ number of employees attending picnic }$

$c \propto n\\\\c = kn$

Where "k" is the constant of proportionality

c = kn ---------- eqn 1

Given that company picnic costs $487.50 for 30 employees

Therefore substitute c = 487.50 and n = 30

$487.50 = k(30)\\\\k = \frac{487.50}{30} = 16.25$

How much does a company picnic cost for 80 employees?

Substitute n = 80 and k = 16.25 in eqn 1

$c = 16.25(80) = 1300$

Thus $ 1300 is the cost for 80 employees

5 0

2 years ago

Please help show that the following are TRUE.

mafiozo [28]

Answer:

see below

Step-by-step explanation:

The formula for the sum of an infinite geometric series with first term a1 and common ratio r (where |r| < 1) is ...

sum = a1/(1 -r)

Applying this to the given series, we get ...

a. sum = 5/(1 -3/4) = 5/(1/4) = 20

b. sum = d/(1 -1/t) = d/((t-1)/t) = dt/(t-1)

_____

The derivation of the above formula is in most texts on sequences and series. In general, you write an expression for the difference of the sum (S) and the product r·S. You find all terms of the series cancel except the first and last, and the last goes to zero in the limit, because r^∞ → 0 for |r| < 1. Hence you get ...

S -rS = a1

S = a1/(1 -r)

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3 years ago

Plz help, answer the question below

Afina-wow [57]

$\sqrt[6]{x^{16}} =\sqrt[6]{x^{12} \cdot x^{4}}=x^2\sqrt[6]{x^{4}}$

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3 years ago