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3 years ago

Can someone please help

Mathematics

1 answer:

erica [24]3 years ago

5 0

Answer:

Step-by-step explanation:

When there is no decomposition, the plant is deficient in minerals.

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According to the properties of inequality, when should the inequality symbol be reversed when solving a two-step any quality in

Marina86 [1]

According to the properties of inequality, we reverse the inequality symbol when we add or multiply by any negative number

Given inequality is Ax + B > C

In the first step, we subtract B from both sides

Ax + B > C

Ax + B - B > C - B

Ax > C - B

Now to remove A we divide by A on both sides

If A is negative then the reverse the inequality sign

When A is negative then > symbol becomes < symbol

so the inequality symbol be reversed when the value of A is negative

3 0

3 years ago

Read 2 more answers

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

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3 years ago

X- (-12)=25 <br><br> ( FIND X)

Dafna11 [192]

Step-by-step explanation:

X- (-12)=25

X+12=25

X=25-12

X=13

please mark as brainliest

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3 years ago

Determine a possible 3rd degree polynomial function in factored form with its only zeros at (4,0) and (-1,0) and (-7,0)

babunello [35]

4,9 equals 17 triven - 3 sued secton, 2 blue suction
And I Purple section
To Find - probability
Solutions:
P
=
Favarable out comes
Total Outcomes
• P/ Land on ried).
3
-N
3+2+1
And p (Lands on blue) = SAT
I
3
And p/Lands on Purple)=
Hence, Answer aol
P(red).
=
P (blue)
=
3
P / Purple :
=-

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2 years ago

Simplify <br><br> 11x-4x+26<br><br> i need help quick

ArbitrLikvidat [17]

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6 0

3 years ago

Read 2 more answers

Can someone please help​

Can someone please help